My NSUI Northeastern StateO XScreenshot 2020-11-27 at 7.20.5...O O Q QGiven the following information:Heat of sublimation of K(s) = 89 kJ/mol%3DBond energy of HF = 565 kJ/molIonization energy of K(g) = 419 kJ/molElectron affinity of F(g) = –328 kJ/mol"attice energy of KF(s) = –808 kJ/mol>Bond energyof H2 = 432 kJ/mol%3DCalculate the net change in energy for the following reaction:2K(s) + 2HF(g) → 2KF(s) + H2 (g)Change in energykJSubmit AnswerTry Another Version3 item attempts remainingO 7:21

Given that Heat of sublimation of K(s)=89kJ/mol Bond energy of HF=565kJ/mol Ionization energy of K (g)=419kJ/mol Electron affinity of F (g)=-328kJ/mol Lattice energy of KF (s)=-808kJ/mol Bond energy of H2=432kJ/mol We have 2K (s) + 2HF (g)→2KF (s) + H2 (g) By using given data, we can construct exact equation as follows K(s)→K(g), Heat of sublimation of K(∆subH)=89kJ/mol HF(g)→H(g) +F(g), Bond energy of Hf=565kJ/mol K(g) →K-(g) +e- , Ionization energy(IE) of K (g) =419kJ/mol F(g) +e-→F-(g), Electron affinity of F(g)=-328kJ/mol K- (g)+F-(g)→KF, Lattice energy of KF(s)(U0)=-808kJ/mol H2(g)→2H(g), Bond energy of H2=432kJ/mol From these data, the net energy change can be calculated as Net energy change =[2 X (∆subH)+(2 X bond energy of HF)+ (2 X IE)+(2 X Electron affinity of F(g))+(2 XU0)-(2 X Bond energy of H2)] =[2 X (89kJ/mol)+(2 X 565kJ/mol)+ (2 X 419kJ/mol)+(2 X -328kJ/mol)+(2 X-808kJ/mol)-(2 X 432kJ/mol)] =-990kJ So change in energy=-990kJ

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Given the following information: Heat of sublimation of K(s) = 89 kJ/mol Bond energy of HF = 565 kJ/mol Ionization energy of K(g) = 419 kJ/mol %3D Electron affinity of F(g) = –328 kJ/mol %3D "Lattice energy of KF(s) = –808 kJ/mol %3D Bond energy of H2 = 432 kJ/mol Calculate the net change in energy for the following reaction: 2K(s) + 2HF(g) → 2KF(s) + H2 (g) Change in energy = kJ %3D

Given the following information: Heat of sublimation of K(s) = 89 kJ/mol Bond energy of HF = 565 kJ/mol Ionization energy of K(g) = 419 kJ/mol %3D Electron affinity of F(g) = –328 kJ/mol %3D "Lattice energy of KF(s) = –808 kJ/mol %3D Bond energy of H2 = 432 kJ/mol Calculate the net change in energy for the following reaction: 2K(s) + 2HF(g) → 2KF(s) + H2 (g) Change in energy = kJ %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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