14. Runtime ComplexityGiven the following implementations of countWays and countWays2, which of the following are the best approximations for the runtime complexities of countWays and countWays2as a function of dist?def countWays(dist):# Base casesif dist < e:return eif dist == 0:return 1return (countWays(dist - 1) + countWays (dist - 2) +countWays(dist - 3))def countWays2(dist):count = (0] • (dist + 1)count[e] - 1if dist > 1:count[1] - 1if dist >= 2:count[2] = 2for i in range(3, dist + 1):count[i] = (count[i - 1] + count[i - 2] + count[1 - 3])return count[dist]Pick ONE optionO countWays: O(dist), countWays2: O(dist)O countWays: O(3^dist), countWays2: O(3^dist)17OcountWays: O(dist!), countWays2: O(dist!)18O countWays: O(3^dist), countWays2: O(dist)19Clear Selection225backspace

While doing programming in any programming language, you need to use various variables to store…

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Computer Networking: A Top-Down Approach (7th Edition)

7th Edition

ISBN:9780133594140

Author:James Kurose, Keith Ross

Publisher:James Kurose, Keith Ross

Chapter1: Computer Networks And The Internet

Section: Chapter Questions

Problem R1RQ: What is the difference between a host and an end system? List several different types of end...

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I am having a hard time understanding the output of this program with shadow and deep binding. Can someone explain it more in detail? I posted the answers below x : integer – – globalprocedure set x(n : integer)x := nprocedure print x()write integer(x)procedure foo(S, P : function; n : integer)x : integer := 5if n in {1, 3}set x(n)elseS(n)174 Chapter 3 Names, Scopes, and Bindingsif n in {1, 2}print x()elsePset x(0); foo(set x, print x, 1); print x()set x(0); foo(set x, print x, 2); print x()set x(0); foo(set x, print x, 3); print x()set x(0); foo(set x, print x, 4); print x() Here are the answers to the questions. The program prints = 10 20 30 40 with shallow binding The program prints = 10 52 00 44 with deep binding,
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