Please give me the answer with proper explanation package eqnparseimport "strconv"// STUDENTS: MODIFY THE IMPLEMENTATIONS TO IMPROVE THE BENCHMARKfunc (expr Expression) String() (s string) {for i:= 0; i < len(expr.Numbers)+len(expr.Operators); i++ {if i%2 == 0 {// evens += strconv.ltoa(expr.Numbers[i/2])} else {// odds += string(expr.Operators[(i-1)/2])}}return}func (eqn Equation) String() string {return eqn.lhs.String() + "=" + eqn.rhs.String()}improve the benchmark of above code

To improve the benchmark of the above code, here are a few suggestions: Replace string…

package eqnparse import "strconv" // STUDENTS: MODIFY THE IMPLEMENTATIONS TO IMPROVE THE BENCHMARK func (expr Expression) String() (s string) { for i:= 0; i < len(expr.Numbers)+len(expr.Operators); i++{ if 1962 == 0 { // even s += strconv.ltoa(expr.Numbers[i/2]) } else { } // odd s += string(expr.Operators[(i-1)/2]) } return } func (eqn Equation) String() string { return eqn.lhs.String() + "=" + eqn.rhs.String() } improve the benchmark of above code

package eqnparse import "strconv" // STUDENTS: MODIFY THE IMPLEMENTATIONS TO IMPROVE THE BENCHMARK func (expr Expression) String() (s string) { for i:= 0; i < len(expr.Numbers)+len(expr.Operators); i++{ if 1962 == 0 { // even s += strconv.ltoa(expr.Numbers[i/2]) } else { } // odd s += string(expr.Operators[(i-1)/2]) } return } func (eqn Equation) String() string { return eqn.lhs.String() + "=" + eqn.rhs.String() } improve the benchmark of above code

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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