Given the following data: CO(g)+H20(g)→ CO,(g)+ H2(g) AH° (25° C) = -42.0 kJmol1 C, (CO) = 26.8 + 6 x 10³T JK'mol1 C, (H2O) = 30.1 + 10 x 10³T JK 'mol1 Co (H2) = 28.5 + 2 x 10³T JK-'mol1 C, (CO2) = 26.4 + 42 x 10³T JK-'mol1 where T is the thermodynamic temperature, calculate the change in enthalpy for the reaction at 1000 K.
Given the following data: CO(g)+H20(g)→ CO,(g)+ H2(g) AH° (25° C) = -42.0 kJmol1 C, (CO) = 26.8 + 6 x 10³T JK'mol1 C, (H2O) = 30.1 + 10 x 10³T JK 'mol1 Co (H2) = 28.5 + 2 x 10³T JK-'mol1 C, (CO2) = 26.4 + 42 x 10³T JK-'mol1 where T is the thermodynamic temperature, calculate the change in enthalpy for the reaction at 1000 K.
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.48QE
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Question
![Given the following data:
CO(g)+H20(g)→ CO,(g)+ H2(g)
AH° (25°C) = -42.0 kJmol1
C, (CO) = 26.8 + 6 x 10³T
JK'mol1
C, (H2O) = 30.1+ 10 x 10³T
JK'mol1
Cp (H2) = 28.5 + 2 x 10³T
JK'mol1
C, (CO2) = 26.4 + 42 x 10³T
JK-'mol1
where T is the thermodynamic temperature, calculate the change in enthalpy for the
reaction at 1000 K.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F47ecbcad-e35a-42de-bebb-c0e9709094ad%2Fb08bc766-1851-4921-b897-6f8a6f5e1926%2Fledo2f_processed.png&w=3840&q=75)
Transcribed Image Text:Given the following data:
CO(g)+H20(g)→ CO,(g)+ H2(g)
AH° (25°C) = -42.0 kJmol1
C, (CO) = 26.8 + 6 x 10³T
JK'mol1
C, (H2O) = 30.1+ 10 x 10³T
JK'mol1
Cp (H2) = 28.5 + 2 x 10³T
JK'mol1
C, (CO2) = 26.4 + 42 x 10³T
JK-'mol1
where T is the thermodynamic temperature, calculate the change in enthalpy for the
reaction at 1000 K.
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