Use the equationAH° ASIn(K)+RTRFor K at two temperatures T₁ and T₂, the equation can be manipulated to give:AHⓇ 1·(₁1/2)K₁ R T₁T₂In =In3.25 x 10-28.94-5.62 =(5.80 × 10-5 mol/J) (AH°)AH = -9.69 x 10¹ J/molFor K = 8.94 at T = 25°C:AH°18.3145 J/K mol 298 KIn(8.94) =AS⁰8.3145= -36.9-(-9.69 × 10¹ J/mol)ASⓇ+(8.3145 J/K.mol) (298 K) 8.3145 J/K . mol1348 KAS-307 J/K.molWe get the same value for AS using K = 3.25 x 10-2 at T = 348 K.b Estimate the temperature where K = 1.00 for this reaction.Temperature =K

Answered: Image /qna-images/answer/24a05c7b-e3c7-425b-9dae-bbb785128499.jpg

Use the equation AS In(K) = R For K at two temperatures T₁ and T₂, the equation can be manipulated to give: K2 AHⓇ 1 1-K-AR (-) In = K₁ In -AHⓇ RT 3.25 x 10-² 8.94 In(8.94) - 5.62 = (5.80 × 10-5 mol/J)(AH°) -9.69 × 10¹ J/mol AH° = For K= 8.94 at T = 25°C: + = = AHⓇ 8.3145 J/K mol 298 K 1 (K-3K) 348 K AS 8.3145 AS = -307 J/K . mol We get the same value for AS using K = 3.25 × 10-² at T = 348 K. - 36.9 -(-9.69 × 10¹ J/mol) ASⓇ (8.3145 J/K-mol) (298 K) 8.3145 J/K - mol Estimate the temperature where K = 1.00 for this reaction. Temperature K

Use the equation AS In(K) = R For K at two temperatures T₁ and T₂, the equation can be manipulated to give: K2 AHⓇ 1 1-K-AR (-) In = K₁ In -AHⓇ RT 3.25 x 10-² 8.94 In(8.94) - 5.62 = (5.80 × 10-5 mol/J)(AH°) -9.69 × 10¹ J/mol AH° = For K= 8.94 at T = 25°C: + = = AHⓇ 8.3145 J/K mol 298 K 1 (K-3K) 348 K AS 8.3145 AS = -307 J/K . mol We get the same value for AS using K = 3.25 × 10-² at T = 348 K. - 36.9 -(-9.69 × 10¹ J/mol) ASⓇ (8.3145 J/K-mol) (298 K) 8.3145 J/K - mol Estimate the temperature where K = 1.00 for this reaction. Temperature K

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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