Given that the moment of inertia of a rod of length L and mass M about an axis passing through its center of mass and perpendicular to the length of the rod is I = 12 MI² and that the moment of inertia of a disk of mass M and radius R about an axis passing through its center of mass is I = MR². a) Calculate the moment of inertia of a thin rod of mass m axis through the rod at d₁ = 0.300L, as shown below. 1 = 2.60 kg and length L = 1.60 m about an d₁ Id₁ b) We now add a disk of mass md d₁ =0.300L, as shown below. d₁ dz = 1.30 kg and radius R = 0.160 m to the rod with its center at dz b) calculate the new moment of inertia about an axis through the rod at d₁ = 0.300L. 12d1 = b) We now add a second disk of mass md at the far end of the rod, as shown below. d₁ = 1.30 kg and radius R = 0.160 m to the rod with its center dz c) calculate the new moment of inertia about an axis through the rod at d₁ = 0.300L. 13d1 =

University Physics Volume 1
18th Edition
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:William Moebs, Samuel J. Ling, Jeff Sanny
Chapter10: Fixed-axis Rotation
Section: Chapter Questions
Problem 10.5CYU: Check Your Understanding What is the moment of inertia of a cylinder of radius R and mass m about an...
icon
Related questions
Question
100%

Don't use chat gpt 

Given that the moment of inertia of a rod of length L and mass M about an axis passing through its center
of mass and perpendicular to the length of the rod is I = 12 MI² and that the moment of inertia of a
disk of mass M and radius R about an axis passing through its center of mass is I = MR².
a) Calculate the moment of inertia of a thin rod of mass m
axis through the rod at d₁ = 0.300L, as shown below.
1
=
2.60 kg and length L
= 1.60 m about an
d₁
Id₁
b) We now add a disk of mass md
d₁ =0.300L, as shown below.
d₁
dz
=
1.30 kg and radius R
=
0.160 m to the rod with its center at
dz
b) calculate the new moment of inertia about an axis through the rod at d₁ = 0.300L.
12d1
=
b) We now add a second disk of mass md
at the far end of the rod, as shown below.
d₁
=
1.30 kg and radius R
= 0.160 m to the rod with its center
dz
c) calculate the new moment of inertia about an axis through the rod at d₁ = 0.300L.
13d1
=
Transcribed Image Text:Given that the moment of inertia of a rod of length L and mass M about an axis passing through its center of mass and perpendicular to the length of the rod is I = 12 MI² and that the moment of inertia of a disk of mass M and radius R about an axis passing through its center of mass is I = MR². a) Calculate the moment of inertia of a thin rod of mass m axis through the rod at d₁ = 0.300L, as shown below. 1 = 2.60 kg and length L = 1.60 m about an d₁ Id₁ b) We now add a disk of mass md d₁ =0.300L, as shown below. d₁ dz = 1.30 kg and radius R = 0.160 m to the rod with its center at dz b) calculate the new moment of inertia about an axis through the rod at d₁ = 0.300L. 12d1 = b) We now add a second disk of mass md at the far end of the rod, as shown below. d₁ = 1.30 kg and radius R = 0.160 m to the rod with its center dz c) calculate the new moment of inertia about an axis through the rod at d₁ = 0.300L. 13d1 =
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
University Physics Volume 1
University Physics Volume 1
Physics
ISBN:
9781938168277
Author:
William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:
OpenStax - Rice University
Classical Dynamics of Particles and Systems
Classical Dynamics of Particles and Systems
Physics
ISBN:
9780534408961
Author:
Stephen T. Thornton, Jerry B. Marion
Publisher:
Cengage Learning
Principles of Physics: A Calculus-Based Text
Principles of Physics: A Calculus-Based Text
Physics
ISBN:
9781133104261
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning
Physics for Scientists and Engineers: Foundations…
Physics for Scientists and Engineers: Foundations…
Physics
ISBN:
9781133939146
Author:
Katz, Debora M.
Publisher:
Cengage Learning
College Physics
College Physics
Physics
ISBN:
9781305952300
Author:
Raymond A. Serway, Chris Vuille
Publisher:
Cengage Learning
Physics for Scientists and Engineers, Technology …
Physics for Scientists and Engineers, Technology …
Physics
ISBN:
9781305116399
Author:
Raymond A. Serway, John W. Jewett
Publisher:
Cengage Learning