Useful formulae: a₁ = w²R. ac F = mã ||=wR, 0(t) — 0(0) = wt. ; ac = v = R |F Gravity = G M1 M2 Newton's universal constant of gravitation: G: R² = 6.674 × 10-11 Nm² (kg)2 Units of work: 1 J = 1 m N Gravity acceleration near the surface of the Earth: g = 9.8 m/s² Problem 2: A small planet of mass Mp = 5 × 1021 kg orbits at a distance R = 1.5 × 10¹¹ m from a star. The star has mass Ms = 2 × 1030 kg (notice that the mass of the star is much greater than the mass of the planet). It is also known that the orbit is circular. Answer the following questions: a) Calculate the centripetal acceleration of the planet Option A: 0.0059 m/s² Option B: 9.8 m/s² Option C: 0.332 9.8 m/s² Option D: 0 m/s² b) Calculate the planet's speed as it travels its orbit Option A: 3,333 m/s Option B: 29,748 m/s Option C: 15,001 m/s Option D: 20 km/h c) Calculate what the centripetal acceleration of the planet would be if it had half the mass that it has. Option A: 0.332 9.8 m/s² Option B: 0.0059 m/s² Option C: 12.243 m/s² Option D: 122.43 m/s² d) If the radius R of the orbit is reduced by half (while the rest of the parameters remain the same), what would happen to the centripetal acceleration of the planet? It would ... Option A: ... be multiplied by 4. Option C: ... be multiplied by 0.5. Option B: ... be multiplied by 2. Option D: ... remain the same. e) If the radius of the orbit is reduced by half, what would happen to the "years" on that planet (i.e. the time required to complete an entire orbit)? The length of the year ... Option A:... would be shortened. Option C: ... would remain the same. Option B: ... would lengthen. Option D: ... depends on the mass of the planet, Mp.
Useful formulae: a₁ = w²R. ac F = mã ||=wR, 0(t) — 0(0) = wt. ; ac = v = R |F Gravity = G M1 M2 Newton's universal constant of gravitation: G: R² = 6.674 × 10-11 Nm² (kg)2 Units of work: 1 J = 1 m N Gravity acceleration near the surface of the Earth: g = 9.8 m/s² Problem 2: A small planet of mass Mp = 5 × 1021 kg orbits at a distance R = 1.5 × 10¹¹ m from a star. The star has mass Ms = 2 × 1030 kg (notice that the mass of the star is much greater than the mass of the planet). It is also known that the orbit is circular. Answer the following questions: a) Calculate the centripetal acceleration of the planet Option A: 0.0059 m/s² Option B: 9.8 m/s² Option C: 0.332 9.8 m/s² Option D: 0 m/s² b) Calculate the planet's speed as it travels its orbit Option A: 3,333 m/s Option B: 29,748 m/s Option C: 15,001 m/s Option D: 20 km/h c) Calculate what the centripetal acceleration of the planet would be if it had half the mass that it has. Option A: 0.332 9.8 m/s² Option B: 0.0059 m/s² Option C: 12.243 m/s² Option D: 122.43 m/s² d) If the radius R of the orbit is reduced by half (while the rest of the parameters remain the same), what would happen to the centripetal acceleration of the planet? It would ... Option A: ... be multiplied by 4. Option C: ... be multiplied by 0.5. Option B: ... be multiplied by 2. Option D: ... remain the same. e) If the radius of the orbit is reduced by half, what would happen to the "years" on that planet (i.e. the time required to complete an entire orbit)? The length of the year ... Option A:... would be shortened. Option C: ... would remain the same. Option B: ... would lengthen. Option D: ... depends on the mass of the planet, Mp.
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Question
Transcribed Image Text:Useful formulae:
a₁ = w²R.
ac
F = mã
||=wR, 0(t) — 0(0) = wt.
;
ac =
v =
R
|F Gravity
=
G M1 M2
Newton's universal constant of gravitation: G:
R²
= 6.674 × 10-11 Nm²
(kg)2
Units of work: 1 J = 1 m N
Gravity acceleration near the surface of the Earth: g = 9.8 m/s²
Transcribed Image Text:Problem 2: A small planet of mass Mp = 5 × 1021 kg orbits at a distance R = 1.5 × 10¹¹ m from a star. The
star has mass Ms = 2 × 1030 kg (notice that the mass of the star is much greater than the mass of the planet).
It is also known that the orbit is circular. Answer the following questions:
a) Calculate the centripetal acceleration of the planet
Option A: 0.0059 m/s²
Option B: 9.8 m/s²
Option C: 0.332 9.8 m/s²
Option D: 0 m/s²
b) Calculate the planet's speed as it travels its orbit
Option A: 3,333 m/s
Option B: 29,748 m/s
Option C: 15,001 m/s
Option D: 20 km/h
c) Calculate what the centripetal acceleration of the planet would be if it had half the mass that it has.
Option A: 0.332 9.8 m/s²
Option B: 0.0059 m/s²
Option C: 12.243 m/s²
Option D: 122.43 m/s²
d) If the radius R of the orbit is reduced by half (while the rest of the parameters remain the same), what
would happen to the centripetal acceleration of the planet? It would ...
Option A: ... be multiplied by 4.
Option C: ... be multiplied by 0.5.
Option B: ... be multiplied by 2.
Option D: ... remain the same.
e) If the radius of the orbit is reduced by half, what would happen to the "years" on that planet (i.e. the time
required to complete an entire orbit)? The length of the year ...
Option A:... would be shortened.
Option C: ... would remain the same.
Option B: ... would lengthen.
Option D: ... depends on the mass of the planet, Mp.
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