Given P(A) = 0.34, P(B) = 0.60, and P(A or B) = 0.24, are events A and B mutually exclusive? %3D %3D %3D
Given P(A) = 0.34, P(B) = 0.60, and P(A or B) = 0.24, are events A and B mutually exclusive? %3D %3D %3D
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![**Problem Statement:**
Given the following probabilities:
- P(A) = 0.34
- P(B) = 0.60
- P(A or B) = 0.24
Determine if events A and B are mutually exclusive.
**Explanation:**
Two events are mutually exclusive if they cannot occur at the same time, meaning the probability of both events happening together is zero, i.e., P(A and B) = 0.
According to the formula for the probability of the union of two events:
\[ P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \]
Plug in the given values:
\[ 0.24 = 0.34 + 0.60 - P(A \text{ and } B) \]
Simplify to find P(A and B):
\[ P(A \text{ and } B) = 0.34 + 0.60 - 0.24 = 0.70 \]
Since P(A and B) ≠ 0, events A and B are not mutually exclusive.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1658d937-8052-45d3-ba3f-7a589de5c533%2F7f7a54c2-ca4d-4d21-bd21-d2b9be991632%2F1u60ku4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Given the following probabilities:
- P(A) = 0.34
- P(B) = 0.60
- P(A or B) = 0.24
Determine if events A and B are mutually exclusive.
**Explanation:**
Two events are mutually exclusive if they cannot occur at the same time, meaning the probability of both events happening together is zero, i.e., P(A and B) = 0.
According to the formula for the probability of the union of two events:
\[ P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \]
Plug in the given values:
\[ 0.24 = 0.34 + 0.60 - P(A \text{ and } B) \]
Simplify to find P(A and B):
\[ P(A \text{ and } B) = 0.34 + 0.60 - 0.24 = 0.70 \]
Since P(A and B) ≠ 0, events A and B are not mutually exclusive.
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