Suppose among a population of students 50% own a laptop and 30% of the total have a laptop but no tablet. Suppose 70% have a laptop, a tablet, or both. Are the probabilities of owning a laptop and a tablet independent? No, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop) Yes, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop) Yes, pr(tablet) x pr(laptop) = 0.2 x 0.5 = f(tablet & laptop) Cannot answer given the info No, pr(tablet) x pr(laptop) = 0.45 x 0.5 != f(tablet & laptop)

College Algebra
7th Edition
ISBN:9781305115545
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter9: Counting And Probability
Section9.3: Binomial Probability
Problem 2E: If a binomial experiment has probability p success, then the probability of failure is...
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Suppose among a population of students 50% own a laptop and 30% of the total have
a laptop but no tablet. Suppose 70% have a laptop, a tablet, or both. Are the
probabilities of owning a laptop and a tablet independent?
No, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop)
Yes, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop)
Yes, pr(tablet) x pr(laptop) = 0.2 x 0.5 = f(tablet & laptop)
Cannot answer given the info
No, pr(tablet) x pr(laptop) = 0.45 x 0.5 != f(tablet & laptop)
Transcribed Image Text:Suppose among a population of students 50% own a laptop and 30% of the total have a laptop but no tablet. Suppose 70% have a laptop, a tablet, or both. Are the probabilities of owning a laptop and a tablet independent? No, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop) Yes, pr(tablet) x pr(laptop) = 0.4 x 0.5 = f(tablet & laptop) Yes, pr(tablet) x pr(laptop) = 0.2 x 0.5 = f(tablet & laptop) Cannot answer given the info No, pr(tablet) x pr(laptop) = 0.45 x 0.5 != f(tablet & laptop)
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