Given P(A) = 0.13, P(B) = 0.02, and P(A or B) = 0.15, are events A and B mutually exclusive?

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Chapter1: Combinatorial Analysis
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Given P(A) = 0.13, P(B) = 0.02, and P(A or B) = 0.15, are events A and B mutually exclusive?

### Explanation:

To determine if events A and B are mutually exclusive, we use the relationship:

\[ P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \]

For mutually exclusive events, \( P(A \text{ and } B) = 0 \).

Substituting the given values:

\[ 0.15 = 0.13 + 0.02 - P(A \text{ and } B) \]

\[ 0.15 = 0.15 - P(A \text{ and } B) \]

\[ P(A \text{ and } B) = 0 \]

Since \( P(A \text{ and } B) = 0 \), events A and B are indeed mutually exclusive.
Transcribed Image Text:Given P(A) = 0.13, P(B) = 0.02, and P(A or B) = 0.15, are events A and B mutually exclusive? ### Explanation: To determine if events A and B are mutually exclusive, we use the relationship: \[ P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \] For mutually exclusive events, \( P(A \text{ and } B) = 0 \). Substituting the given values: \[ 0.15 = 0.13 + 0.02 - P(A \text{ and } B) \] \[ 0.15 = 0.15 - P(A \text{ and } B) \] \[ P(A \text{ and } B) = 0 \] Since \( P(A \text{ and } B) = 0 \), events A and B are indeed mutually exclusive.
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