The events E, F and G have the following properties:   P(E)=0.32 P(F)=0.39 P(G)=0.28P(E)=0.32 P(F)=0.39 P(G)=0.28   P(EUF)=P(EUF)=0.60   P(EUG)=0.45 P(FUG)=0.44P(EUG)=0.45 P(FUG)=0.44   P(E∩F∩G)=P(E∩F∩G)=0.04   Compute the probability that at least one of E,FE,F or GG occur; that is, compute P(EUFUG)P(EUFUG). Use two decimal place accuracy.

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