Given: Mass of block =M Angle of incline 0 Length of incline S Height of incline = h Height(h) - S sin o S = Force equation in direction vertical to Incline : N- Mg cos ở = M X0 [Since there is no motion vertically, so accleration = 0] N = Mg cos e .. Equation(1) Force equation in direction horizontal to Incline : uN - Mg sin o = M x -a [Since there is motion horizontally down, so accleration = -a] U sin g equation (1). H(Mg cos ) - Mg sin 0 = MX(-a) - a EIME CIn -My sin M Mela cos -sin d a = g (sin - pı cos 0) a- g sin o (1- S sin a- g sin 0(1 - pcot 0) ..... Equation(2) U sin g 3rd equation of motion v2 = u? + 2as where. V final velocity - initial velocity a = acceleration S = displacement U sin g equation (2). =0 + 2 (g sin e(1 - pcot 0)S v = 2g sin 0(1 - µcot 0)S Also, sin ce S -. vV2g sin 0(1 - pcot 0) v- /2gh(1- pcot 0) Change in Gravitational Potential Energy: Gravitional Potential Energy = mass x height x acceleration due to gravity U = mgh Change in Potential energy = Potential energy at height h - Potential energy at height 0 AU = Mgh - Mg x 0 AU = Mgh or MgS AU = [Since S = h sin o sin 6
Given: Mass of block =M Angle of incline 0 Length of incline S Height of incline = h Height(h) - S sin o S = Force equation in direction vertical to Incline : N- Mg cos ở = M X0 [Since there is no motion vertically, so accleration = 0] N = Mg cos e .. Equation(1) Force equation in direction horizontal to Incline : uN - Mg sin o = M x -a [Since there is motion horizontally down, so accleration = -a] U sin g equation (1). H(Mg cos ) - Mg sin 0 = MX(-a) - a EIME CIn -My sin M Mela cos -sin d a = g (sin - pı cos 0) a- g sin o (1- S sin a- g sin 0(1 - pcot 0) ..... Equation(2) U sin g 3rd equation of motion v2 = u? + 2as where. V final velocity - initial velocity a = acceleration S = displacement U sin g equation (2). =0 + 2 (g sin e(1 - pcot 0)S v = 2g sin 0(1 - µcot 0)S Also, sin ce S -. vV2g sin 0(1 - pcot 0) v- /2gh(1- pcot 0) Change in Gravitational Potential Energy: Gravitional Potential Energy = mass x height x acceleration due to gravity U = mgh Change in Potential energy = Potential energy at height h - Potential energy at height 0 AU = Mgh - Mg x 0 AU = Mgh or MgS AU = [Since S = h sin o sin 6
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Pls explain in DETAIL the FORMULA and EQUATIONS and how did you come up with the solution. I need to present it in class and I didn't know how
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