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Diving board A Length : 4m Width : 0.45m Thickness : 0.03m Inertial of moment: I=bh 1=(0.45)(0.03)" 1= 1.0125 x 10-*m* Wx,+ 1. = 5(-¿wco)" +=w(0) – 12w) V2 = (69Gpa)(1.0125 x 10-"m*) -12(686.7) Vz = (69Gpa)(1.0125 x 10-*m*) V = 0.11m

Diving board A Length : 4m Width : 0.45m Thickness : 0.03m Inertial of moment: I=bh 1=(0.45)(0.03)" 1= 1.0125 x 10-*m* Wx,+ 1. = 5(-¿wco)" +=w(0) – 12w) V2 = (69Gpa)(1.0125 x 10-"m*) -12(686.7) Vz = (69Gpa)(1.0125 x 10-*m*) V = 0.11m

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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write some paragraphs explaining this calculation.

my be one paragraph is enough.

i am doing the discussion so I need your help 

 

Diving board A Length : 4m Width : 0.45m Thickness : 0.03m Inertial of moment: I= bh 12 (0.45)(0.03) I = 1.0125 x 10-m Vz = --Wx2 + c3X2 + 1 wx +Wx. - 12w) V2 = 1 (696pa)(1.0125 x 10-“m*)(-÷wo» +w0)- 12w) -12(686.7) (69Gpa) (1.0125 x 10-6m*) Vz = V2 = 0.11m
Transcribed Image Text:Diving board A Length : 4m Width : 0.45m Thickness : 0.03m Inertial of moment: I= bh 12 (0.45)(0.03) I = 1.0125 x 10-m Vz = --Wx2 + c3X2 + 1 wx +Wx. - 12w) V2 = 1 (696pa)(1.0125 x 10-“m*)(-÷wo» +w0)- 12w) -12(686.7) (69Gpa) (1.0125 x 10-6m*) Vz = V2 = 0.11m
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