Diving board A Length : 4m Width : 0.45m Thickness : 0.03m Inertial of moment: I=bh 1=(0.45)(0.03)" 1= 1.0125 x 10-*m* Wx,+ 1. = 5(-¿wco)" +=w(0) – 12w) V2 = (69Gpa)(1.0125 x 10-"m*) -12(686.7) Vz = (69Gpa)(1.0125 x 10-*m*) V = 0.11m

Diving board A Length : 4m Width : 0.45m Thickness : 0.03m Inertial of moment: I=bh 1=(0.45)(0.03)" 1= 1.0125 x 10-m Wx,+ 1. = 5(-¿wco)" +=w(0) – 12w) V2 = (69Gpa)(1.0125 x 10-"m) -12(686.7) Vz = (69Gpa)(1.0125 x 10-m*) V = 0.11m

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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write some paragraphs explaining this calculation.

my be one paragraph is enough.

i am doing the discussion so I need your help

Diving board A
Length : 4m
Width : 0.45m
Thickness : 0.03m
Inertial of moment:
I= bh
12
(0.45)(0.03)
I = 1.0125 x 10-m
Vz =
--Wx2 + c3X2 +
1
wx +Wx. - 12w)
V2 =
1
(696pa)(1.0125 x 10-“m*)(-÷wo» +w0)- 12w)
-12(686.7)
(69Gpa) (1.0125 x 10-6m*)
Vz =
V2 = 0.11m

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