Given: Kc = 4,8 mA/V ;b = 7 mA Sensor range: 0-10V Actuator range: 4-20 mA Question: How big is the proportional band?
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Q: 4: What is the equivalent resister of the network shown? А: 1 В: 2 С: 3 D: 4
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Q: 1 (a) Using Townsend's second ionization criterion, consider Io = 4 x 10-7 A. Consider a = 2.28/cm.…
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Q: 2. The concentration of donor impurity atoms in silicon is Nd 1015 cm-3. Assume an electron mobility…
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Q: The concentration of donor impurity atoms in doped silicon is Na = 1015 cm-3 Assume an electron…
A: Solution:-Given thatNd=1015 cm-3μn=1600 cm2Vsμp=450 cm2Vs
Q: Q3] Find the resistivity at 300 K for a Si sample doped with 1.0x104 cm of phosphorous atoms, 8.5x…
A: Formula:ρ=1niqμn+μpohm·cmwhere, ρ is the resistivityni=9.65×109cm-3q=1.6×10-19Cμn=1500 cm2/V·sμp=500…
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Q: | Find the resistivity at 300 K for a Si sample doped with 1.0x10 cm' of phosphorous atoms, 8.5x 102…
A: Write the given value of this problem. Phosphorus atom=1×1014 cm-3Arsenic atom=8.5×1012 cm-3Boron…
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Q: Circuit #3: & = 6 V, &2 = E3 = 3 V,and R = R, = 10 2. Direction: E2 Current through A: right / left…
A: (a)Current through A. (b)voltage across R2. given data: ε1=6 Vε2=ε3=3 VR1=R2=10 Ω
Q: 2. The concentration of donor impurity atoms in silicon is Nd = 1015 cm-3. Assume an electron…
A: electron mobility μe=1300cm2/V-s hole mobility μp=450cm2/V-s concentration n=1015cm-3 conductivity…
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Q: 1. Calculate the potential due to a dipole as shown in the figure at positions A and B in millivolts
A: “Since you have asked multiple questions, we will solve the first question for you. If you want any…
Q: 3: What is the equivalent resister of the network shown? A: 5 25L 22 В: 2 a С: 3 D: 6
A: Given data: Three resistors are connected in series R1 = 1 Ω, R2 = 2 Ω and R3 = 2 Ω Required: The…
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Q: A 56 cn long superconductor is connected to a 120 V power supply and produces infinite current.…
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Q: 7. The nominal resistance value of the a 4-band resistor is 470 kQ ± 5%. a. What is the resistance…
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Q: The Electronic Current through an electronic device is due to the flow of both electrons and holes.…
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