g) If the reaction was carried out at 200°C instead, the concentrations of the ammonia and the carbon dioxide were lower than when the reaction was carried out 250°C. Use this information to determine if the reaction is endothermic or exothermic, and be sure I can follow your reasoning (try to be concise, please!).
g) If the reaction was carried out at 200°C instead, the concentrations of the ammonia and the carbon dioxide were lower than when the reaction was carried out 250°C. Use this information to determine if the reaction is endothermic or exothermic, and be sure I can follow your reasoning (try to be concise, please!).
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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I just need help with part g please
Thank you
![Consider the reaction:
NH2COONH4 (s) = 2 NH3 (g) + CO2 (g)
At high temperatures such as 250.°C, the equilibrium constant for the reaction is 1.58 x 10-8. A research
student ran the experiment by first placing 39.1 g of the reactant compound in a 750. mL evacuated closed
container. (R = 0.08206 L.atm/K.mol; K = °C + 273; pay attention to sig figs)
a) Write the equilibrium expression, Kc, for this reaction.
kc=l.58 x 10
COONH
kc [NH3]? [COz]
b) What is the concentration of each of the products at equilibrium?
NH2COONH4 (s) = 2 NH3 (g) + CO2 (g)
NHz COON H4: 39.1g
78.070 gimol
50 mol
NH2 COON Hy = Z NH3 CO2
Tnitial -50 gimo1
W 999.
+ 2 X
t ズ
ミGGG N
•150L
E
: 666-X
answer: ENHS] = 2(-89x104)
:1.78x10-4 M
C COz] = -89x 10 4 M
kc CNH3]?CCO1] →1.58* 10°8-(2x) Cx)
2x2.1.58x 1
X: 1.58x108
c) What is the pressure in atm exerted by each of the products at equilibrium?
on
79x 10
こ、
kp= kc x (RT)
X= .89x104
R=. 08206
kp:1.58x10-8 x(.08206x523)?
:1,58 x 108x (42.91738)?
: 2.9|x 10-5
n (3-1) = 2
入
T 523 k
-5
[NH3]=2(,0302) = . O605 altm
X= .0302
COL): 10302 atm
d) Use these pressures to calculate the Kp for the reaction at this temperature.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc15907a8-70f3-4470-885a-42b8107f503f%2F8c356ad1-7ab1-4f5c-b772-afdde6a87e22%2F8tv4vnk_processed.png&w=3840&q=75)
Transcribed Image Text:Consider the reaction:
NH2COONH4 (s) = 2 NH3 (g) + CO2 (g)
At high temperatures such as 250.°C, the equilibrium constant for the reaction is 1.58 x 10-8. A research
student ran the experiment by first placing 39.1 g of the reactant compound in a 750. mL evacuated closed
container. (R = 0.08206 L.atm/K.mol; K = °C + 273; pay attention to sig figs)
a) Write the equilibrium expression, Kc, for this reaction.
kc=l.58 x 10
COONH
kc [NH3]? [COz]
b) What is the concentration of each of the products at equilibrium?
NH2COONH4 (s) = 2 NH3 (g) + CO2 (g)
NHz COON H4: 39.1g
78.070 gimol
50 mol
NH2 COON Hy = Z NH3 CO2
Tnitial -50 gimo1
W 999.
+ 2 X
t ズ
ミGGG N
•150L
E
: 666-X
answer: ENHS] = 2(-89x104)
:1.78x10-4 M
C COz] = -89x 10 4 M
kc CNH3]?CCO1] →1.58* 10°8-(2x) Cx)
2x2.1.58x 1
X: 1.58x108
c) What is the pressure in atm exerted by each of the products at equilibrium?
on
79x 10
こ、
kp= kc x (RT)
X= .89x104
R=. 08206
kp:1.58x10-8 x(.08206x523)?
:1,58 x 108x (42.91738)?
: 2.9|x 10-5
n (3-1) = 2
入
T 523 k
-5
[NH3]=2(,0302) = . O605 altm
X= .0302
COL): 10302 atm
d) Use these pressures to calculate the Kp for the reaction at this temperature.

Transcribed Image Text:g) If the reaction was carried out at 200°C instead, the concentrations of the ammonia and the carbon
dioxide were lower than when the reaction was carried out 250°C. Use this information to determine
if the reaction is endothermic or exothermic, and be sure I can follow your reasoning (try to be concise,
please!).
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