Methanol (CH3OH) is converted to bromomethane (CH3B1) as follows: CH3OH + HBr CH3B + H20 If 12.23 g of bromomethane are produced when 5.00 g of methanol is reacted with excess HBr, what is the percentage yield? Multiple Choice 12.9% 33.8% 59.1%

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Methanol (CH3OH) is converted to bromomethane (CH3Br) as follows:
CH3OH + HBr CH3B + H20
If 12.23 g of bromomethane are produced when 5.00 g of methanol is reacted with excess HBr, what is the percentage yield?
Multiple Choice
12.9%
33.8%
59.1%
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Transcribed Image Text:Help Save & Exit Submit Methanol (CH3OH) is converted to bromomethane (CH3Br) as follows: CH3OH + HBr CH3B + H20 If 12.23 g of bromomethane are produced when 5.00 g of methanol is reacted with excess HBr, what is the percentage yield? Multiple Choice 12.9% 33.8% 59.1% < Prev 7 of 15 Next > 2:41 PM 11-Mar-2. asus COLLECTION prt sc delete 12/A 7 (3) & %3D 8.
33.8%
59.1%
40.9%
82.6%
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Transcribed Image Text:33.8% 59.1% 40.9% 82.6% < Prev 7 of 15 Next > asus COLLECTION 112/A prt sc delete insert f7 f8
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