From the Lewis structures of the species given, pick all of those in which the central atom obeys the octet rule. :Ci: Ci-c-ci: :Br-Be-Br: :či: :Ci-P-CI: Above

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Chapter1: Chemical Foundations
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**Question:**

From the Lewis structures of the species given, pick all of those in which the central atom obeys the octet rule.

**Options:**

1. **Option 1:**
   - Lewis structure of a nitrogen atom double-bonded to two oxygen atoms and single-bonded to one fluorine atom.

2. **Option 2:**
   - Lewis structure of a carbon atom single-bonded to four chlorine atoms.

3. **Option 3:**
   - Lewis structure of a beryllium atom single-bonded to two bromine atoms.

4. **Option 4:**
   - Lewis structure of a phosphorus atom single-bonded to five chlorine atoms.

5. **Option 5:**
   - None of the Above

**Explanation of Diagrams:**

- **Option 1:** The central nitrogen atom has two double bonds with oxygen and a single bond with fluorine, including lone pairs on each surrounding atom.
  
- **Option 2:** The central carbon atom is surrounded symmetrically by four chlorine atoms, each with three lone pairs, following the octet rule.
  
- **Option 3:** The central beryllium atom is bonded to two bromine atoms, each with three lone pairs. Beryllium does not follow the octet rule here.
  
- **Option 4:** The central phosphorus atom is surrounded by five chlorine atoms, each with three lone pairs, exceeding the octet rule.

Remember to carefully evaluate each structure to determine compliance with the octet rule.
Transcribed Image Text:**Question:** From the Lewis structures of the species given, pick all of those in which the central atom obeys the octet rule. **Options:** 1. **Option 1:** - Lewis structure of a nitrogen atom double-bonded to two oxygen atoms and single-bonded to one fluorine atom. 2. **Option 2:** - Lewis structure of a carbon atom single-bonded to four chlorine atoms. 3. **Option 3:** - Lewis structure of a beryllium atom single-bonded to two bromine atoms. 4. **Option 4:** - Lewis structure of a phosphorus atom single-bonded to five chlorine atoms. 5. **Option 5:** - None of the Above **Explanation of Diagrams:** - **Option 1:** The central nitrogen atom has two double bonds with oxygen and a single bond with fluorine, including lone pairs on each surrounding atom. - **Option 2:** The central carbon atom is surrounded symmetrically by four chlorine atoms, each with three lone pairs, following the octet rule. - **Option 3:** The central beryllium atom is bonded to two bromine atoms, each with three lone pairs. Beryllium does not follow the octet rule here. - **Option 4:** The central phosphorus atom is surrounded by five chlorine atoms, each with three lone pairs, exceeding the octet rule. Remember to carefully evaluate each structure to determine compliance with the octet rule.
**Transcription for Educational Website**

---

**Periodic Table Overview:**

- The periodic table displayed categorizes elements in a traditional layout. Key groups include:
  - Group 1A: Alkali Metals (e.g., H, Li)
  - Group 2A: Alkaline Earth Metals
  - Transition Metals occupy the center.
  - Group 7A: Halogens (e.g., F, Cl)
  - Group 8A: Noble Gases (e.g., He, Ne)

**Iodine and Bonding:**

- The element iodine is positioned in Group 7A with the halogens. In this context, iodine would be expected to form **one** covalent bond to obey the octet rule.

**Predicting Compound Formation:**

- Using the octet rule, predict the formula of the compound that iodine forms with chlorine. Given that the molecule contains only one iodine atom and forms only single bonds, the predicted formula is **ICl**.

--- 

**Note:** The periodic table aids in understanding the element groups and predicting bonding behaviors in chemical compounds.
Transcribed Image Text:**Transcription for Educational Website** --- **Periodic Table Overview:** - The periodic table displayed categorizes elements in a traditional layout. Key groups include: - Group 1A: Alkali Metals (e.g., H, Li) - Group 2A: Alkaline Earth Metals - Transition Metals occupy the center. - Group 7A: Halogens (e.g., F, Cl) - Group 8A: Noble Gases (e.g., He, Ne) **Iodine and Bonding:** - The element iodine is positioned in Group 7A with the halogens. In this context, iodine would be expected to form **one** covalent bond to obey the octet rule. **Predicting Compound Formation:** - Using the octet rule, predict the formula of the compound that iodine forms with chlorine. Given that the molecule contains only one iodine atom and forms only single bonds, the predicted formula is **ICl**. --- **Note:** The periodic table aids in understanding the element groups and predicting bonding behaviors in chemical compounds.
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