From the following heats of combustion,CH3OH(!) + 3/202(g) → CO2(g) + 2H2O(I)A,H° = -726.4 kJ mol-4,H° = -393.5 kJ mol-A,H° = -285.5 kJ mol¬C(graphite) + O2(g) → CO2(g)1H2(g) + ½O2(g) → H20(1)Calculate the enthalpy of formation of methanol (CH3OH) from its elements:C(graphite) + 2H2(g) +½O2(g) → CH;OH(I)

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From the following heats of combustion, CH;OH(1) + 3/2O2(g) → CO2(g) + 2H2O(1) A,H° = -726.4 kJ mol C(graphite) + O2(g) → CO2(g) A,H° = -393.5 kJ mol H2(g) + ½O2(g) → H2O(!) A,H° = -285.5 kJ mol- Calculate the enthalpy of formation of methanol (CH3OH) from its elements: C(graphite) + 2H2(g) +½O2(g) CH3OH(!)

From the following heats of combustion, CH;OH(1) + 3/2O2(g) → CO2(g) + 2H2O(1) A,H° = -726.4 kJ mol C(graphite) + O2(g) → CO2(g) A,H° = -393.5 kJ mol H2(g) + ½O2(g) → H2O(!) A,H° = -285.5 kJ mol- Calculate the enthalpy of formation of methanol (CH3OH) from its elements: C(graphite) + 2H2(g) +½O2(g) CH3OH(!)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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