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From a mole balance of the gas-phase reactor below, the following expression is obtained for dCA/dt, dCB/dt, and dCc/dt. The density, volume, and temperature are constant. 2A-> B (-rak₁CA) = BC (-гB k₂CB) = F(CAL-CA) = V dCA dt dCB dt dcc dt = || = -F - V CB+ 0.5k₁CA - K₂CB -Cc + k₂CB³ —– k₁CA Fi, CAi V F.CA.CIL.CO F, CA,CB.CC (a) What is the value of CB at steady-state (your answer must be simplified)? (b) List the states, inputs, and parameters for the system.

From a mole balance of the gas-phase reactor below, the following expression is obtained for dCA/dt, dCB/dt, and dCc/dt. The density, volume, and temperature are constant. 2A-> B (-rak₁CA) = BC (-гB k₂CB) = F(CAL-CA) = V dCA dt dCB dt dcc dt = || = -F - V CB+ 0.5k₁CA - K₂CB -Cc + k₂CB³ —– k₁CA Fi, CAi V F.CA.CIL.CO F, CA,CB.CC (a) What is the value of CB at steady-state (your answer must be simplified)? (b) List the states, inputs, and parameters for the system.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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From a mole balance of the gas-phase reactor below, the following expression is obtained for dCA/dt, dCB/dt, and dCc/dt. The density, volume, and temperature are constant. 2A-> B (-rak₁CA) = BC (-гB k₂CB) = F(CAL-CA) = V dCA dt dCB dt dcc dt = || = -F - V CB+ 0.5k₁CA - K₂CB -Cc + k₂CB³ —– k₁CA Fi, CAi V F.CA.CIL.CO F, CA,CB.CC (a) What is the value of CB at steady-state (your answer must be simplified)? (b) List the states, inputs, and parameters for the system.
Transcribed Image Text:From a mole balance of the gas-phase reactor below, the following expression is obtained for dCA/dt, dCB/dt, and dCc/dt. The density, volume, and temperature are constant. 2A-> B (-rak₁CA) = BC (-гB k₂CB) = F(CAL-CA) = V dCA dt dCB dt dcc dt = || = -F - V CB+ 0.5k₁CA - K₂CB -Cc + k₂CB³ —– k₁CA Fi, CAi V F.CA.CIL.CO F, CA,CB.CC (a) What is the value of CB at steady-state (your answer must be simplified)? (b) List the states, inputs, and parameters for the system.
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