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Q: A charged ball is fired straight up, starting from a point at which the electric potential is +200…
A: Given Initial Voltage V = + 200 V Final Voltage V’ = +700 V Charge on the ball q = -10 x 10-3 C Mass…
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Q: A charged ball is fired straight up, starting from a point at which the electric potential is +200…
A: The direction of the electric field is always in the direction of decrease of the potential.
how can we determine whether the following is a conservative force? If it's conservative, what's its potential?
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- A charged ball is fired straight up, starting from a point at which the electric potential is +200 V. The equipotentials are equally spaced, as shown in the picture below, with successive lines in the picture being exactly 1.00 meter apart. This is done at the surface of the Earth, where the gravitational field has a value of q = 10.0 m/s?, directed straight down. The ball has a mass of 150 grams, and the magnitude of the charge on the ball is 10 millicoulombs. +800 V +700 V +600 V +500 V +400 V +300 V 1.00 m +200 V (a) In what direction is the electric field in this situation? O The direction of the field depends on whether the ball has a positive charge or a negative charge. O It's directed vertically, but we can't tell whether it is up or down. O It's directed to the left. O It's directed to the right. O It's directed down. O It's directed horizontally, but we can't tell whether it is left or right. O It's directed up. (b) If the ball has a positive charge, what initial velocity…(0,0,0) and the 5. The point o is the origin of the coordinate system, o = coordinates of b are b = (x,y, z). The electric potential at o is zero, V, = 0. Hence, the electric potential at b is V = – E · dr. You can take any path from o to b. (a) Here is one particular path from o to b. First move on a straight line from o to a = : (x,0,0), then from a to a' = (x, Y, 0), and finally from a' to b = (x, y, z). Make a plot of this path, indicating the coordinate system and the locations of a, a' and b. – SE • dr depends only on the y However, the line integral V coordinate of b = (x, y, z). Hence, in the following, we will focus on b = (0, y, 0) and take the straight path from o to b. (b) Compute E · dr for y d result, use this potential next.The figure below shows a system of two charged particles and several labeled test locations. We will set V = 0 infinitely far away. A +Q d B * C +Q d H D
- Predict: what is the ratio of the final energy to the initial energy, Uf/Ui, if the final state has been achieved by the following sequence of steps (starting from the initial situation)? Initial Area is 100 mm^2 and initial separation distance is 10 mm. the battery is disconnected the area is quadrupled the dielectric is taken out of the capacitor the separation is halved. Recreate the the table previously given below. Add a column to solve for the ratio.(a) Find the energy in Joules that needs to be expanded to assemble the threecharges in the Figure. (b) Find the electrical potential at a point halfway between the bottomcharges. (c) What is the magnitude in N/C of electrical field at a point half way between thebottom charges? (d) Determine the direction of electrical field found in part c. (e) What is themagnitude of the force acting on the corner charge? please answer all partA Q load is placed at each of the opposite vertices of a square. Another q load is placed at each of the other two vertices of the square. A) If the resulting force over Q is zero, what is the ratio (Q/q), between Q and q loads? B) Calculate the electrical potential at each of the midpoints on the sides of the square. The side of the square is 10 cm and Q is +20uc.
- (a) A solid cylindrical conductor of radius a and charge Q is coaxial with a cylindrical shell of negligible thickness, radius b > a, and charge -Q (as shown in the figure). The length of the cylindrical conductor is 1. Show that the capacitance of this cylindrical capacitor is C= 2rE, In(b/a)` (b) A coaxial cable used in a transmission line has an inner radius of 0.10 mm and an outer radius of 0.50 mm. Calculate the capacitance for a 1- meter long cable. Assume that the space between the conductors is filled with substance having dielectric constant « = 4find where E = 0, given V(x,y) = 2xy - x^2-y. E is the electric field and V(x,y) is the potential. I see that x = 0.5 and y= 0.5 but i dont understand the processA proton is released from rest at x=2m in the potential shown. What does the proton do immediately after being released? V (V) 50 - x (m) 1 3 -50 Move to the right with increasing speed. Move to the left with increasing speed. Stay at x=2m. Move to the right with constant speed. Move to the left with constant speed. 2.
- A charged ball is fired straight up, starting from a point at which the electric potential is +200 V. The equipotentials are equally spaced, as shown in the picture below, with successive lines in the 10.0 m/s², directed straight down. The ball has a mass of 200 grams, = picture being exactly 1.00 meter apart. This is done at the surface of the Earth, where the gravitational field has a value of g and the magnitude of the charge on the ball is 10 millicoulombs. 1.00 m Vi +800 V +700 V +600 V +500 V +400 V +300 V +200 VConsider a negative charge q placed in a uniform electric field as shown in thefigure below. Find the change in the electric potential energy ∆Uelec for these cases:(1) The charge moves up distance d.(2) The charge moves down distance d.(3) The charge moves sideways (90◦ to E~ ).For problem 31 of the text, calculate the potential at point P in uV for the case that the removed part of the disk subtends an angle of 204.0 degrees instead of three quadrants!! (5 sig figs)