(0, 0,0) and the 5. The point o is the origin of the coordinate system, o = coordinates of b are b = (x,y, z). The electric potential at o is zero, V. = 0. Hence, the electric potential at b is V = - SE· dr. You can take any path from o to b. (a) Here is one particular path from o to b. First move on a straight line from o to a = (x,0,0), then from a to a' (x, y, 0), and finally from a' to b = (x, y, z). Make a plot of this path, indicating the coordinate system and the locations of a, a' and b. – sE · dr depends only on the y However, the line integral V coordinate of b = (x, y, z). Hence, in the following, we will focus on b = (0, y, 0) and take the straight path from o to b. (b) Compute E · dr for y < 0. (c) Compute sE · dr for 0 < y < d. What is the value of the electric pontential at b = (0, d, 0)?

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(0,0,0) and the
5. The point o is the origin of the coordinate system, o =
coordinates of b are b = (x,y, z). The electric potential at o is zero,
V, = 0. Hence, the electric potential at b is V = – E · dr. You can
take any path from o to b.
(a) Here is one particular path from o to b. First move on a straight line
from o to a =
: (x,0,0), then from a to a' = (x, Y, 0), and finally from
a' to b = (x, y, z). Make a plot of this path, indicating the coordinate
system and the locations of a, a' and b.
– SE • dr depends only on the y
However, the line integral V
coordinate of b = (x, y, z). Hence, in the following, we will focus on
b = (0, y, 0) and take the straight path from o to b.
(b) Compute E · dr for y < 0.
(c) Compute E dr for 0 < y < d. What is the value of the electric
pontential at b = (0, d, 0)?
(d) Compute E · dr for d < y.
(e) Combine the results of (b), (c), (d) to compute the electric potential
V, and plot V as a function of y.
for y <0
€0
The answer is V
for 0 < y <d. If that was not your
(y – d) for y > d
result, use this potential next.
Transcribed Image Text:(0,0,0) and the 5. The point o is the origin of the coordinate system, o = coordinates of b are b = (x,y, z). The electric potential at o is zero, V, = 0. Hence, the electric potential at b is V = – E · dr. You can take any path from o to b. (a) Here is one particular path from o to b. First move on a straight line from o to a = : (x,0,0), then from a to a' = (x, Y, 0), and finally from a' to b = (x, y, z). Make a plot of this path, indicating the coordinate system and the locations of a, a' and b. – SE • dr depends only on the y However, the line integral V coordinate of b = (x, y, z). Hence, in the following, we will focus on b = (0, y, 0) and take the straight path from o to b. (b) Compute E · dr for y < 0. (c) Compute E dr for 0 < y < d. What is the value of the electric pontential at b = (0, d, 0)? (d) Compute E · dr for d < y. (e) Combine the results of (b), (c), (d) to compute the electric potential V, and plot V as a function of y. for y <0 €0 The answer is V for 0 < y <d. If that was not your (y – d) for y > d result, use this potential next.
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