A thin rod has uniform charge per length 3w over its length H. The distance between point A and point B is 3H and the distance between point A and point P is 2H.We introduce an integration variables with 5 = 0 chosen to be at point A and the +s direction to be down. The small red segment has length ds and charge dg. We want to find the electric potential atpoint P.Draw it out--label the all the lengths and the integration variable!A. dV=B. dVC. dV =D. dV=AWhich expression below gives the voltage d'V from the small charge dg in the small segment ds? Choose from the choices (A thru F) below:E. dV=F. dV=BсKdq√√²+4H²Kdg(s² +4H²)Kdq5Kdq√(8+3H)² +4H²Kdg((s+3H)² +4H²)3.Kdq H((8+6H)² +97²)³/2-P+y>+xWhat are the limits of integration s? [Select][Select]

Answered: Image /qna-images/answer/d26771ac-e6a1-4242-b968-c5a1d7bfdc12.jpg

thin rod has uniform charge per length 3w over its length H. The distance between point A and point B is 3H and the distance between point A and point P is 2H. fe introduce an integration variables with 5 = 0 chosen to be at point A and the +s direction to be down. The small red segment has length ds and charge dq. We want to find the electric potential at pint P. raw it out -- label the all the lengths and the integration variable! - dv= - dv= hich expression below gives the voltage dy from the small charge de in the small segment ds? Choose from the choices (A thru F) below: [Select] Kdg √²+4H1² dV= dV= C dV= dV= Kdq (s²+4H²) Kdg $ Kdq √(s+3H)²+4H² Kdg ((s+3H)² +4H²) 3Kdq H ((s+6H)² +9H²)2/2 P L... What are the limits of integration s? [Select]

thin rod has uniform charge per length 3w over its length H. The distance between point A and point B is 3H and the distance between point A and point P is 2H. fe introduce an integration variables with 5 = 0 chosen to be at point A and the +s direction to be down. The small red segment has length ds and charge dq. We want to find the electric potential at pint P. raw it out -- label the all the lengths and the integration variable! - dv= - dv= hich expression below gives the voltage dy from the small charge de in the small segment ds? Choose from the choices (A thru F) below: [Select] Kdg √²+4H1² dV= dV= C dV= dV= Kdq (s²+4H²) Kdg $ Kdq √(s+3H)²+4H² Kdg ((s+3H)² +4H²) 3Kdq H ((s+6H)² +9H²)2/2 P L... What are the limits of integration s? [Select]

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

A thin rod has uniform charge per length 3w over its length H. The distance between point A and point B is 3H and the distance between point A and point P is 2H.
We introduce an integration variables with 5 = 0 chosen to be at point A and the +s direction to be down. The small red segment has length ds and charge dg. We want to find the electric potential at
point P.
Draw it out--label the all the lengths and the integration variable!
A. dV=
B. dV
C. dV =
D. dV=
A
Which expression below gives the voltage d'V from the small charge dg in the small segment ds? Choose from the choices (A thru F) below:
E. dV=
F. dV=
B
с
Kdq
√√²+4H²
Kdg
(s² +4H²)
Kdq
5
Kdq
√(8+3H)² +4H²
Kdg
((s+3H)² +4H²)
3.Kdq H
((8+6H)² +97²)³/2
-P
+y
>+x
What are the limits of integration s? [Select]
[Select]

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