3. A thin non-conducting rod of length has a total charge q uni- formly distributed over its length. The point P is a distance y above the rod such that it is a perpendicular bisector of the rod. This is shown below. V(y) = (a) Show that the magnitude of the electric potential at point P is given by 9 Σπερ P l+√4y² + 1² 2y Here we take V = 0 at infinity. (b) Hence find the magnitude of the electric field at point P. Ans: (b) E(y) In I 9 2περυν 4y2+ (2 IY е
3. A thin non-conducting rod of length has a total charge q uni- formly distributed over its length. The point P is a distance y above the rod such that it is a perpendicular bisector of the rod. This is shown below. V(y) = (a) Show that the magnitude of the electric potential at point P is given by 9 Σπερ P l+√4y² + 1² 2y Here we take V = 0 at infinity. (b) Hence find the magnitude of the electric field at point P. Ans: (b) E(y) In I 9 2περυν 4y2+ (2 IY е
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Transcribed Image Text:3. A thin non-conducting rod of length l has a total charge q uni-
formly distributed over its length. The point P is a distance y
above the rod such that it is a perpendicular bisector of the rod.
This is shown below.
P
(a) Show that the magnitude of the electric potential at point P is
given by
V (y)
е
l
201²-1 in (²+√4x²+2)
Σπερ
2y
Here we take V = 0 at infinity.
(b) Hence find the magnitude of the electric field at point P.
Ans: (b) E(y) =
9
2περ! | 4y2 + (2
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