Given an electric potential of V= 4πεο Γ find its corresponding electric field vector. Sol. Using the concept of potential gradient, we have Ê = - V Since we only have, radial direction (r). Then, the del-operator will be = P. By substitution, we get È = - - Evaluating the differential, we, get the following 1 È = *(q/ 4πεο

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Chapter1: Units, Trigonometry. And Vectors
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Given an electric potential of

 

find its corresponding electric field vector.

Sol.

Using the concept of potential gradient, we have

 

Since we only have, radial direction (r). Then, the del-operator will be

 

By substitution, we get

 

Evaluating the differential, we, get the following

 *(q/)

Given an electric potential of
V=
4 πεο Γ
find its corresponding electric field vector.
Sol.
Using the concept of potential gradient, we have
È = - V
Since we only have, radial direction (r). Then, the del-operator will be
V =?-
By substitution, we get
Evaluating the differential, we, get the following
1
*(q/
4πεο
Transcribed Image Text:Given an electric potential of V= 4 πεο Γ find its corresponding electric field vector. Sol. Using the concept of potential gradient, we have È = - V Since we only have, radial direction (r). Then, the del-operator will be V =?- By substitution, we get Evaluating the differential, we, get the following 1 *(q/ 4πεο
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