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(d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 270 V potential difference. Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q₁ = | after pC PC Determine the capacitance (in F) and potential difference (in V) after immersion. Cf AV, = Determine the change in energy (in nj) of the capacitor. V

(d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 270 V potential difference. Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q₁ = | after pC PC Determine the capacitance (in F) and potential difference (in V) after immersion. Cf AV, = Determine the change in energy (in nj) of the capacitor. V

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Could you please help me out with part What if (d) and so on?

Please write out the solution,that way I can follow along and understand the steps, if it's in the "typed out" format is confusing to follow the thought process. Thank you so much!!

An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 270 V. Assume a plate separation of d = 1.61 cm and a plate area of A = 25.0 cm². When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0. (a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q₁ after Qf = = (b) Determine the capacitance (in F) and potential difference (in V) after immersion. Cf = AV f = F V pC pC (c) Determine the change in energy (in nJ) of the capacitor. AU = nJ (d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 270 V potential difference. Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q₁ pC pC after Qf = Determine the capacitance (in F) and potential difference (in V) after immersion. Cf AV f = F V Determine the change in energy (in nJ) of the capacitor. AU = | n]
Transcribed Image Text:An engineer working in an electronics lab connects a parallel-plate capacitor to a battery, so that the potential difference between the plates is 270 V. Assume a plate separation of d = 1.61 cm and a plate area of A = 25.0 cm². When the battery is removed, the capacitor is plunged into a container of distilled water. Assume distilled water is an insulator with a dielectric constant of 80.0. (a) Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q₁ after Qf = = (b) Determine the capacitance (in F) and potential difference (in V) after immersion. Cf = AV f = F V pC pC (c) Determine the change in energy (in nJ) of the capacitor. AU = nJ (d) What If? Repeat parts (a) through (c) of the problem in the case that the capacitor is immersed in distilled water while still connected to the 270 V potential difference. Calculate the charge on the plates (in pC) before and after the capacitor is submerged. (Enter the magnitudes.) before Q₁ pC pC after Qf = Determine the capacitance (in F) and potential difference (in V) after immersion. Cf AV f = F V Determine the change in energy (in nJ) of the capacitor. AU = | n]
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