A thin rod has total charge 3W spread out uniformly over its length H. The distance between point A and point B is 3H and the distance between point A and point P is 2H. We introduce an integration variables with s = 0 chosen to be at point A and the+s direction to be down. The small red segment has length ds and charge dq. We want to find the electric potential at point P. Draw it out--label the all the lengths and the integration variable! A. dV= B. dV= C. dV= What is the charge dq in the small segment ds? [Select] Which expression below gives the voltage d'V from the small charge da in the small segment ds? Choose from the choices (A thru F) below: [Select] D. dV= E. dV= A F. B dV = Kdg (8² +4H²) Kdq Vs² +4H² Kdq ((s+3H)² +4H1²) 3Kdg H ((3+6H)² +97²)3/2 Kdq √(s+3H)² +4H² P +y Kdq 8 >+x

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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A thin rod has total charge 3W spread out uniformly over its length H. The distance between point A and point B is 3H and the distance between point A and point P is 2H.
We introduce an integration variables with 5 = 0 chosen to be at point A and the+s direction to be down. The small red segment has length ds and charge dq. We want to find the electric potential at
point P.
Draw it out--label the all the lengths and the integration variable!
A. dV=
B. dV=
What is the charge dq in the small segment ds? [Select]
C. dV=
Which expression below gives the voltage dV from the small charge dag in the small segment ds? Choose from the choices (A thru F) below:
D.
E. dV=
F.
A
dV =
B
dV=
Kdq
(8² +4H²)
Kdq
Vs² +4H²
Kdq
√(s+3H)² + 4H²
Kdg
((s+3H)²+4H1²)
3Kdg H
((s+6H)² +97²)³/2
P
>+x
Kdq
8
[Select]
Transcribed Image Text:A thin rod has total charge 3W spread out uniformly over its length H. The distance between point A and point B is 3H and the distance between point A and point P is 2H. We introduce an integration variables with 5 = 0 chosen to be at point A and the+s direction to be down. The small red segment has length ds and charge dq. We want to find the electric potential at point P. Draw it out--label the all the lengths and the integration variable! A. dV= B. dV= What is the charge dq in the small segment ds? [Select] C. dV= Which expression below gives the voltage dV from the small charge dag in the small segment ds? Choose from the choices (A thru F) below: D. E. dV= F. A dV = B dV= Kdq (8² +4H²) Kdq Vs² +4H² Kdq √(s+3H)² + 4H² Kdg ((s+3H)²+4H1²) 3Kdg H ((s+6H)² +97²)³/2 P >+x Kdq 8 [Select]
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