Consider the geometry shown in the figure below. The lengths of the plates in the x and z directions are ∞. The width of plate 1 in the y direction is L=2. The potential on plates 2 and 3 are 0. The potential on plate 1 is V. = sin²(7 y). (1) Use separation of variables to find the potential V(x, y). Keep up to 3rd terms. (2) Plot V(x = 0, y) as a function of y. (3) Plot V(x, y = 1) as a function of x. y L=2 V.(v) -Z Plate 1 0 V=0 V=0 Plate 2 Plate 3 X
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- In the figure below, what is the net electric potential at point P due to the four particles, if V = 0 at infinity, q = 4.50 fC, and d = 4.50 cm? ____________VV(V) In the right figure, the top panel of graph shows the potential V as a function of position x in three regions I, II, and III. Accordingly, four parallel plates, A through D, can be setup to realized the distribution of potential, as schematically drawn in the bottom panel of the figure. The unit of the distance is cm, and the unit of potential is V. 10 ↑ II III 5. 2. 6. 8 x(cm) -5- The potential on plate B is -10- V Submit Answer Tries 0/2 The magnitude (i.e. absolute value) of the electric field in region I is I II II V/m 4 x(cm Submit Answer Tries 0/2 A particle carries -18e charge (i.e. q = В С C. -2.88x10-18 region III. Its initial velocity is zero at position x = 8 cm. When it leaves region III, how much is the kinetic energy of this particle in eV (electron-volt)? C) and is free to move in eVThe charge density on a disk of radius R = 11.8 cm is given by o = ar, with a = 1.36 µC/m³ and r measured radially outward from the origin (see figure below). What is the electric potential at point A, a distance of 36.0 cm above the disk? Hint: You will need to integrate the nonuniform charge density to find the electric potential. You will find a table of integrals helpful for performing the integration. V A
- The two charges in the figure below are separated by d = 2.50 cm. (Let q1 = −17.5 nC and q2 = 26.0 nC.) Find the electric potential at point A. in kVFind the electric potential at point B, which is halfway between the charges. in kVIn three corners of a square with d=4 cm side length, there are point charges (in red) Q1=10 pC, Q2 =97 pC and Q3 =119 pC. Calculate the difference between the potentials in the middle (V2) and in the fourth corner (V1) . (V2-V1) Write your answer in V with 2 decimals.please write the steps clearly. thank you
- The charge density on a disk of radius R = 12.6 cm is given by o = ar, with a = 1.34 μC/m³ and r measured radially outward from the origin (see figure below). What is the electric potential at point A, a distance of 36.0 cm above the disk? Hint: You will need to integrate the nonuniform charge density to find the electric potential. You will find a table of integrals helpful for performing the integration. X Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. V R AAt a distance d from a charge, the electric potential is V. What would be the electric potential a distance d/2 from the same charge?Please asap
- A uniform electric field of magnitude 7.8×105 N/C points in the positive x direction. Find the change in electric potential between the origin and the point (0, 6.0 m). Express your answer using one significant figure. Find the change in electric potential between the origin and the point (6.0 m, 0). Express your answer using two significant figures. Find the change in electric potential between the origin and the point (6.0 m, 6.0 m). Express your answer using two significant figures.A charged conducting spherical shell of radius R = 3 m with total charge q = 23 μC produces the electric field given by E⃗ (r)={014πϵ0qr2r̂ forforr<Rr>R(PICTURE ATTACHED OF EQUATION) a. Enter an expression for the electric potential inside the sphere ( r < R ) in terms of the given quantities, assuming the potential is zero at infinity. V(r)= b. Calculate the electric potential, in volts, at radius r inside the charged shell. V(r) =An isolated charged soap bubble of radius Ro = 4.65 cm is at a potential of V= 283.0 volts. If the bubble shrinks to a ridios that is 39.0% of the initial radius, by how much does its electrostatic potential energy U change? Assume that the charge on the bubble is spread evenly over the surface, and that the total charge on the bubble remains constant. AU = Upd- Unl = TOOLS x10