### Electric Potential Calculation for Charged Particles**Problem Statement:**The three charged particles in the figure below are at the vertices of an isosceles triangle (where \(d = 4.80 \, \text{cm}\)). Taking \(q = 8.10 \, \mu\text{C}\), calculate the electric potential at point \(A\), the midpoint of the base.**Diagram Explanation:**The diagram depicts an isosceles triangle with three charged particles at its vertices. The charges are arranged as follows:- A positive charge \(+q\) (represented in orange) is located at the top vertex of the triangle.- Two negative charges \(-q\) (represented in blue) are located at the bottom two vertices of the triangle. The lengths from the positive charge to each of the negative charges are \(2d\) and the length from each negative charge to the midpoint \(A\) is \(d\).**Steps for Calculation:**1. **Understand the Layout:** The triangle is isosceles with the following measurements: - Distance from the positive charge to each negative charge: \(2d\) - Distance from each negative charge to the midpoint \(A\): \(d\)2. **Calculate the Electric Potential at Point \(A\):** The electric potential \(V\) at a point due to a charge is given by the formula: \[ V = \frac{kq}{r} \] where: - \(k\) is Coulomb's constant \((8.99 \times 10^9 \, \text{N m}^2 / \text{C}^2)\) - \(q\) is the charge - \(r\) is the distance from the charge to the point Given: \[ q = 8.10 \, \mu\text{C} = 8.10 \times 10^{-6} \, \text{C} \] \[ d = 4.80 \, \text{cm} = 0.048 \, \text{m} \] - Electric potential due to the positive charge \(+q\) at point \(A\): \[ V_1 = \frac{k \times q}{2

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The three charged particles in the figure below are at the vertices of an isosceles triangle (where d = 4.80 cm). Taking q = 8.10 µC, calculate the electric potential at point A, the midpoint of the base. %3D

The three charged particles in the figure below are at the vertices of an isosceles triangle (where d = 4.80 cm). Taking q = 8.10 µC, calculate the electric potential at point A, the midpoint of the base. %3D

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Question

### Electric Potential Calculation for Charged Particles

**Problem Statement:**
The three charged particles in the figure below are at the vertices of an isosceles triangle (where \(d = 4.80 \, \text{cm}\)). Taking \(q = 8.10 \, \mu\text{C}\), calculate the electric potential at point \(A\), the midpoint of the base.

**Diagram Explanation:**
The diagram depicts an isosceles triangle with three charged particles at its vertices. The charges are arranged as follows:
- A positive charge \(+q\) (represented in orange) is located at the top vertex of the triangle.
- Two negative charges \(-q\) (represented in blue) are located at the bottom two vertices of the triangle.

The lengths from the positive charge to each of the negative charges are \(2d\) and the length from each negative charge to the midpoint \(A\) is \(d\).

**Steps for Calculation:**
1. **Understand the Layout:**
The triangle is isosceles with the following measurements:
- Distance from the positive charge to each negative charge: \(2d\)
- Distance from each negative charge to the midpoint \(A\): \(d\)

2. **Calculate the Electric Potential at Point \(A\):**

The electric potential \(V\) at a point due to a charge is given by the formula:
\[
V = \frac{kq}{r}
\]
where:
- \(k\) is Coulomb's constant \((8.99 \times 10^9 \, \text{N m}^2 / \text{C}^2)\)
- \(q\) is the charge
- \(r\) is the distance from the charge to the point

Given:
\[
q = 8.10 \, \mu\text{C} = 8.10 \times 10^{-6} \, \text{C}
\]
\[
d = 4.80 \, \text{cm} = 0.048 \, \text{m}
\]

- Electric potential due to the positive charge \(+q\) at point \(A\):
\[
V_1 = \frac{k \times q}{2

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