Consider an air-gapped parallel-plate capacitor (you can use E0= 8.85x10^-12 C^2/ (N x m^2)). The capacitor has a capacitance of 20 nF and a charge of magnitude 0.30 mC on each plate. Then, the potential difference between the plates is _V. Express answer in exponential format with 3 significant figures. Continuing with the previous question, if the plates are 0.45 mm apart, the area of each plate is m². Use normal format and 3 SF. Let's continue. If the capacitor is discharged and then connected to a 11.6 V battery, and the distance between the plates is changed to 1.00 mm, then the magnitude of the electric field between the plates is N/C. Use exponential format and 3 SF.
Consider an air-gapped parallel-plate capacitor (you can use E0= 8.85x10^-12 C^2/ (N x m^2)). The capacitor has a capacitance of 20 nF and a charge of magnitude 0.30 mC on each plate. Then, the potential difference between the plates is _V. Express answer in exponential format with 3 significant figures. Continuing with the previous question, if the plates are 0.45 mm apart, the area of each plate is m². Use normal format and 3 SF. Let's continue. If the capacitor is discharged and then connected to a 11.6 V battery, and the distance between the plates is changed to 1.00 mm, then the magnitude of the electric field between the plates is N/C. Use exponential format and 3 SF.
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Chapter1: Units, Trigonometry. And Vectors
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Question
![Consider an air-gapped parallel-plate capacitor (you can use E0= 8.85x10^-12 C^2/(N x m^2)).
The capacitor has a capacitance of 20 nF and a charge of magnitude 0.30 mC on each plate.
Then, the potential difference between the plates is
V. Express answer in
exponential format with 3 significant figures.
Continuing with the previous question, if the plates are 0.45 mm apart, the area of each plate is
2
m². Use normal format and 3 SF.
Let's continue. If the capacitor is discharged and then connected to a 11.6 V battery, and the
distance between the plates is changed to 1.00 mm, then the magnitude of the electric field
between the plates is
N/C. Use exponential format and 3 SF.
The electric energy stored in a 20 nF capacitor charged by a 81.1 V battery is
Use exponential format and 3 SF.
J.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2acbc49c-c62a-42f8-908e-1d1265b1d299%2F05a2d246-2b09-431f-bb11-75254b80117b%2Frqavf6_processed.png&w=3840&q=75)
Transcribed Image Text:Consider an air-gapped parallel-plate capacitor (you can use E0= 8.85x10^-12 C^2/(N x m^2)).
The capacitor has a capacitance of 20 nF and a charge of magnitude 0.30 mC on each plate.
Then, the potential difference between the plates is
V. Express answer in
exponential format with 3 significant figures.
Continuing with the previous question, if the plates are 0.45 mm apart, the area of each plate is
2
m². Use normal format and 3 SF.
Let's continue. If the capacitor is discharged and then connected to a 11.6 V battery, and the
distance between the plates is changed to 1.00 mm, then the magnitude of the electric field
between the plates is
N/C. Use exponential format and 3 SF.
The electric energy stored in a 20 nF capacitor charged by a 81.1 V battery is
Use exponential format and 3 SF.
J.
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