A parallel plate capacitor is constructed of two square plates, size L × L, separated by a distance d . The plates are given, respectively +Q and -Q charge. Consider all these quantities initial values, and we sequentially change the parameters such that they have different final values. If we alter Q( charge), to create a Qf (final charge)that is different than Qi( initial charge)what is the ratio of electric filed Ef /Ei, meaning how does the electric field inside the capacitor change? If we doubled L, what is the ratio of Ef /Ei? Lastly, consider the case where we only doubled d( distance)compute the ratio of Ef /Ei electric field.
A parallel plate capacitor is constructed of two square plates, size L × L, separated by a distance d . The plates are given, respectively +Q and -Q charge. Consider all these quantities initial values, and we sequentially change the parameters such that they have different final values. If we alter Q( charge), to create a Qf (final charge)that is different than Qi( initial charge)what is the ratio of electric filed Ef /Ei, meaning how does the electric field inside the capacitor change? If we doubled L, what is the ratio of Ef /Ei? Lastly, consider the case where we only doubled d( distance)compute the ratio of Ef /Ei electric field.
Hint:
You have to make a statement on what happens when you change the charges of the plates. Say... by giving some numerical values as examples. And use the formula to find E electric field. Change in initial and final charge will give you the answer
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