Find H at (0,0,5) due to side 2 of the triangular loop in figure 7.6(a).

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Find H at (0,0,5) due to side 2 of the triangular loop in figure 7.6(a).
as
10 A
10 A
(b)
(a)
FIGURE 7.6 For Example 7.1: (a) conducting triangular loop, (b) side 1 of the
loop.
Hence,
10
cos a,)a,
(cos az
%3D
H =
29
4πρ
- -59.la, mA/m
%3D
Transcribed Image Text:Find H at (0,0,5) due to side 2 of the triangular loop in figure 7.6(a). as 10 A 10 A (b) (a) FIGURE 7.6 For Example 7.1: (a) conducting triangular loop, (b) side 1 of the loop. Hence, 10 cos a,)a, (cos az %3D H = 29 4πρ - -59.la, mA/m %3D
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