True or false for question 1: if false exlplain why A)The directed derivative of the voltage gives a vector that points in the direction of the closest local maximum of the voltage. Due to the minus sign in the relationship between E~ and V , it can be concluded that electric fields point from high voltages to low voltages, otherwise known as “downhill” B) ) The equation E = −∆V/∆l is always true, for every situation.

True or false for question 1: if false exlplain why A)The directed derivative of the voltage gives a vector that points in the direction of the closest local maximum of the voltage. Due to the minus sign in the relationship between E~ and V , it can be concluded that electric fields point from high voltages to low voltages, otherwise known as “downhill” B) ) The equation E = −∆V/∆l is always true, for every situation.

Similar questions

Needs Complete typed solution with 100 % accuracy.
for y d €0 result, use this potential next. aV i+ i+ k) for y < 0, 0 < y < d 6. (a) Now compute -VV and d < y. - (b) Should your result agree with the electric field E that you calculated in problem 2? Does it agree? 7. What is the value of the integral f E· dr over a closed path? You need to be special clear and compelling here to arn the points. 8. (a) Describe the equipotential surfaces with V = –5,000 Volts. Where are they located? (b) Is there an equipotential volume? If the answer is "yes," describe it. (c) Describe all the equipotential surfaces V = V, for Vo < 0 fixed but arbitrary. Where are they located as a function of Vo?
Consider two long, parallel, and oppositely charged wires with linear charge density +λ and -λ of radius r with their centers separated by a distance D (? ≫ ?). Show that the capacitance per unit length of this pair of wires is given by the following, and show the work required to set up an integral for E, ∆? and then finding C.
Consider a thin, uniformly charged rod of length L with total charge Q and test points A, a distance a from the center of the rod and B a distance b from the rod. В Find the potential difference between A and B first by integrating the point source potential to find V and V and subtracting, and then by integrating the field. Compare the results in the limit of L>>(a and b). To test the far field limit, compare the appropriate result to the case where L is much less than both a and b. You may need to do this one numerically.
How do you do this one? Specifically, for b), the answer gives Vb > Va, why is that? In general how do we know which side has higher potentials? (notice: this is not a graded question, it's a practice problem that comes with an answer which I don't quite understand, you can see from how I asked the question that the answer is provided...)
Needs Complete solution with 100 % accuracy.