radial line and has a magnitude of 1.28 X 10-21 C.m. What is the net electric potential at the center? •31 SSM WWW A plastic disk of radius R = 64.0 cm is charged on one side with a uniform surface R D Figure 24-50 Problem 31. charge density σ= 7.73 fC/m², and then three quadrants of the disk are removed. The remaining quadrant is shown in Fig. 24-50. With V = 0 at infinity, what is the potential due to the remaining quad- rant at point P, which is on the central axis of the original disk at distance D = 25.9 cm from the original center? h F C t

icon
Related questions
Question

For problem 31 of the text, calculate the
potential at point P in uV for the case that the removed part of the disk subtends an angle of 176.0 degrees instead of three quadrants. Answer in 5 sig figs!!!

QUESTION 4
For problem 24.31 of the text, calculate the
potential at point P in µV for the case that the
removed part of the disk subtends an angle of
176.0 degrees instead of three quadrants. (5 sig.
figs.)
Transcribed Image Text:QUESTION 4 For problem 24.31 of the text, calculate the potential at point P in µV for the case that the removed part of the disk subtends an angle of 176.0 degrees instead of three quadrants. (5 sig. figs.)
radial line and has a magnitude of
1.28 x 10-21 C.m.
What is the net electric potential at
the center?
PA
R
D
Figure 24-50 Problem 31.
•31 SSM www A plastic disk of
radius R = 64.0 cm is charged on
one side with a uniform surface
charge density σ = 7.73 fC/m²,
and then three quadrants of the disk
are removed. The remaining quadrant is shown in Fig. 24-50. With
V = 0 at infinity, what is the potential due to the remaining quad-
rant at point P, which is on the central axis of the original disk at
distance D = 25.9 cm from the original center?
h
F
с
t
Transcribed Image Text:radial line and has a magnitude of 1.28 x 10-21 C.m. What is the net electric potential at the center? PA R D Figure 24-50 Problem 31. •31 SSM www A plastic disk of radius R = 64.0 cm is charged on one side with a uniform surface charge density σ = 7.73 fC/m², and then three quadrants of the disk are removed. The remaining quadrant is shown in Fig. 24-50. With V = 0 at infinity, what is the potential due to the remaining quad- rant at point P, which is on the central axis of the original disk at distance D = 25.9 cm from the original center? h F с t
Expert Solution
steps

Step by step

Solved in 2 steps with 1 images

Blurred answer