Four Forces Force Direction 1-component y-component TNT (*) 60° 160° 260° 325 R+F F = mg g = 9.80 m/s? R = Resultant Force = F1 + F2 + F3 %3D m1 = 0.155 kg, m2 = 0.205 kg, m3 = 0.105 kg, m4 = 0.167 kg Analysis 1. Calculate the magnitude of these forces (F1, F2, F3, F4, R) in newtons and their x/y components. Record these values on your data sheet.
Four Forces Force Direction 1-component y-component TNT (*) 60° 160° 260° 325 R+F F = mg g = 9.80 m/s? R = Resultant Force = F1 + F2 + F3 %3D m1 = 0.155 kg, m2 = 0.205 kg, m3 = 0.105 kg, m4 = 0.167 kg Analysis 1. Calculate the magnitude of these forces (F1, F2, F3, F4, R) in newtons and their x/y components. Record these values on your data sheet.
Related questions
Question
Transcribed Image Text:Four Forces
Force
Direction
1-component
y-component
INT
()
60°
160°
260°
325
R+ F.
F = mg
g = 9.80 m/s?
R = Resultant Force = F1 + F2 + F3
m1 = 0.155 kg,
m2 = 0.205 kg,
m3 = 0.105 kg,
m4 = 0.167 kg
%3D
%3D
Analysis
1. Calculate the magnitude of these forces (F1, F2, F3, F4, R) in newtons and
their x/y components. Record these values on your data sheet.
2. In this system, what was R + Fa? What should this sum be? Why?
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
