T5 Two forces, of magnitudes F= 85.0 N and F₂ = 35.0N, act in opposite directions on a block, which sitsatop a frictionless surface, as shown in the figure.(Figure 1)Initially, the center of the block is at position=-5.00 cm. At some later time, the block hasmoved to the right, and its center is at a new position,z = 6.00 cm.Figure< 1 of 1ReviewPart AFind the work W₁ done on the block by the force of magnitude F₁ = 85.0 N as theblock moves from a = -5.00 cm to y = 6.00 cm.Express your answer numerically, in joules.> View Available Hint(s)—| ΑΣΦW₁JSubmitPart BXoxPart BFind the work W2 done by the force of magnitude F₂ = 35.0 N as the block moves₁ = -5.00 cm to xf = 6.00 cm.Express your answer numerically, in joules.►View Available Hint(s)ΠΫΠΙ ΑΣΦW2 =J>

Given that, The magnitude of the forces are F1=85NF2=35N the initial position of the box is…

Two forces, of magnitudes Fi=85.0 N and F₂ = 35.0 N, act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1)Initially, the center of the block is at position z = -5.00 cm. At some later time, the block has moved to the right, and its center is at a new position, z = 6.00 cm. Figure < 1 of 1 > Review Part A Find the work W, done on the block by the force of magnitude F₁ = 85.0 N as the block moves from = -5.00 cm to y = 6.00 cm. Express your answer numerically, in joules. ▸ View Available Hint(s) ΤΕΙ ΑΣΦΑ ? W₁ Submit J Part B AC X-RX1 Part B Find the work W₂ done by the force of magnitude F₂ = 35.0 N as the block moves 2₁ = -5.00 cm to xf = 6.00 cm. Express your answer numerically, in joules.

Two forces, of magnitudes Fi=85.0 N and F₂ = 35.0 N, act in opposite directions on a block, which sits atop a frictionless surface, as shown in the figure. (Figure 1)Initially, the center of the block is at position z = -5.00 cm. At some later time, the block has moved to the right, and its center is at a new position, z = 6.00 cm. Figure < 1 of 1 > Review Part A Find the work W, done on the block by the force of magnitude F₁ = 85.0 N as the block moves from = -5.00 cm to y = 6.00 cm. Express your answer numerically, in joules. ▸ View Available Hint(s) ΤΕΙ ΑΣΦΑ ? W₁ Submit J Part B AC X-RX1 Part B Find the work W₂ done by the force of magnitude F₂ = 35.0 N as the block moves 2₁ = -5.00 cm to xf = 6.00 cm. Express your answer numerically, in joules.