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The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the tension force F and the force F which hold the arm in equilibrium. (Let 0 = 24.0°.) Assume the weight of the arm is 48.3 N. 8.00 cm N N -29.0 cm-

The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the tension force F and the force F which hold the arm in equilibrium. (Let 0 = 24.0°.) Assume the weight of the arm is 48.3 N. 8.00 cm N N -29.0 cm-

Question
The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the tension force \( \vec{F_t} \) and the force \( \vec{F_s} \) which hold the arm in equilibrium. (Let \( \theta = 24.0^\circ \).) Assume the weight of the arm is 48.3 N. **Diagram Explanation:** - The diagram illustrates an arm with forces acting upon it. - \( \vec{F_t} \) is depicted as a tension force acting in the upward direction at an angle \( \theta = 24.0^\circ \) from the horizontal line running through point O. - \( \vec{F_s} \) is shown as a horizontal force to the left, starting from point O. - \( \vec{F_g} \) represents the gravitational force acting downward from point A, where the center of mass is located. - Distances are marked: the distance between point O and the center of mass A is 29.0 cm, and the horizontal distance from point O where \( \vec{F_t} \) acts is 8.00 cm. **Equation Inputs:** - \( |\vec{F_t}| \) N - \( |\vec{F_s}| \) N This exercise involves calculating the forces required to keep the arm in equilibrium, using the provided angles and distances.
Transcribed Image Text:The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the tension force \( \vec{F_t} \) and the force \( \vec{F_s} \) which hold the arm in equilibrium. (Let \( \theta = 24.0^\circ \).) Assume the weight of the arm is 48.3 N. **Diagram Explanation:** - The diagram illustrates an arm with forces acting upon it. - \( \vec{F_t} \) is depicted as a tension force acting in the upward direction at an angle \( \theta = 24.0^\circ \) from the horizontal line running through point O. - \( \vec{F_s} \) is shown as a horizontal force to the left, starting from point O. - \( \vec{F_g} \) represents the gravitational force acting downward from point A, where the center of mass is located. - Distances are marked: the distance between point O and the center of mass A is 29.0 cm, and the horizontal distance from point O where \( \vec{F_t} \) acts is 8.00 cm. **Equation Inputs:** - \( |\vec{F_t}| \) N - \( |\vec{F_s}| \) N This exercise involves calculating the forces required to keep the arm in equilibrium, using the provided angles and distances.
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