Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the tension force F and the force F which hold the arm in equilibrium. (Let 0 = 24.0°.) Assume the weight of the arm is 48.3 N. 8.00 cm N N -29.0 cm-

The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the tension force F and the force F which hold the arm in equilibrium. (Let 0 = 24.0°.) Assume the weight of the arm is 48.3 N. 8.00 cm N N -29.0 cm-

icon
Related questions
Question
The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the tension force \( \vec{F_t} \) and the force \( \vec{F_s} \) which hold the arm in equilibrium. (Let \( \theta = 24.0^\circ \).) Assume the weight of the arm is 48.3 N. **Diagram Explanation:** - The diagram illustrates an arm with forces acting upon it. - \( \vec{F_t} \) is depicted as a tension force acting in the upward direction at an angle \( \theta = 24.0^\circ \) from the horizontal line running through point O. - \( \vec{F_s} \) is shown as a horizontal force to the left, starting from point O. - \( \vec{F_g} \) represents the gravitational force acting downward from point A, where the center of mass is located. - Distances are marked: the distance between point O and the center of mass A is 29.0 cm, and the horizontal distance from point O where \( \vec{F_t} \) acts is 8.00 cm. **Equation Inputs:** - \( |\vec{F_t}| \) N - \( |\vec{F_s}| \) N This exercise involves calculating the forces required to keep the arm in equilibrium, using the provided angles and distances.
Transcribed Image Text:The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the tension force \( \vec{F_t} \) and the force \( \vec{F_s} \) which hold the arm in equilibrium. (Let \( \theta = 24.0^\circ \).) Assume the weight of the arm is 48.3 N. **Diagram Explanation:** - The diagram illustrates an arm with forces acting upon it. - \( \vec{F_t} \) is depicted as a tension force acting in the upward direction at an angle \( \theta = 24.0^\circ \) from the horizontal line running through point O. - \( \vec{F_s} \) is shown as a horizontal force to the left, starting from point O. - \( \vec{F_g} \) represents the gravitational force acting downward from point A, where the center of mass is located. - Distances are marked: the distance between point O and the center of mass A is 29.0 cm, and the horizontal distance from point O where \( \vec{F_t} \) acts is 8.00 cm. **Equation Inputs:** - \( |\vec{F_t}| \) N - \( |\vec{F_s}| \) N This exercise involves calculating the forces required to keep the arm in equilibrium, using the provided angles and distances.
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 4 steps with 3 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer