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Formaldehyde (CH20) reacts with potassium permanganate (KMNO,) under neutral conditions to form formic acid (CH202) and Mn02. What is the reducing agent? CH20 What is the oxidizing agent? KMN04 How many electrons are involved in the overall reaction? (positive integers only) 12 Fill in the missing information to balance the equation: Hint: Mno, is one of the products, so what medium should you use to balance? H2CO + H20 + 1 Mno, - 1 H2CO2 + 1 Mno2 + 2 OH

Formaldehyde (CH20) reacts with potassium permanganate (KMNO,) under neutral conditions to form formic acid (CH202) and Mn02. What is the reducing agent? CH20 What is the oxidizing agent? KMN04 How many electrons are involved in the overall reaction? (positive integers only) 12 Fill in the missing information to balance the equation: Hint: Mno, is one of the products, so what medium should you use to balance? H2CO + H20 + 1 Mno, - 1 H2CO2 + 1 Mno2 + 2 OH

Chemistry
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Formaldehyde (CH20) reacts with potassium permanganate (KMNO4) under neutral conditions to form formic acid (CH202) and Mn02. What is the reducing agent? CH20 What is the oxidizing agent? KMN04 How many electrons are involved in the overall reaction? (positive integers only) 12 Fill in the missing information to balance the equation: Hint: Mno, is one of the products, so what medium should you use to balance? 1. H2CO + H20 + 1 Mno, - 1 H2CO2 + 1 Mno2 + 2 OH
Transcribed Image Text:Formaldehyde (CH20) reacts with potassium permanganate (KMNO4) under neutral conditions to form formic acid (CH202) and Mn02. What is the reducing agent? CH20 What is the oxidizing agent? KMN04 How many electrons are involved in the overall reaction? (positive integers only) 12 Fill in the missing information to balance the equation: Hint: Mno, is one of the products, so what medium should you use to balance? 1. H2CO + H20 + 1 Mno, - 1 H2CO2 + 1 Mno2 + 2 OH
A mixture of 5.0g A, 5.0 g B, and 5.0 g C were separated by recrystallization using ethyl acetate as the recrystalli solvent. Shown below are the solubilities (in g/100 mL solvent) of A, B, and C in ethyl acetate. C A cold hot cold hot cold Hot 1.7 2.5 2.2 3.6 1.6 5.3 What is the percent purity of the obtained crystal after one recrystallization? Answer: 42.86 A mixture of 5.0 gA, 5.0 g B, and 5.0 g C were separated by recrystallization using ethyl acetate as the recrystallization solvent. Shown below are the solubilities (in g/100 mL solvent) of A, B, and C in ethyl acetate. A B C cold hot cold hot cold Hot 1.7 2.5 2.2 3.6 1.6 5.3 What is the percent recovery of the purified crystal after one recrystallization? Answer: 51.33
Transcribed Image Text:A mixture of 5.0g A, 5.0 g B, and 5.0 g C were separated by recrystallization using ethyl acetate as the recrystalli solvent. Shown below are the solubilities (in g/100 mL solvent) of A, B, and C in ethyl acetate. C A cold hot cold hot cold Hot 1.7 2.5 2.2 3.6 1.6 5.3 What is the percent purity of the obtained crystal after one recrystallization? Answer: 42.86 A mixture of 5.0 gA, 5.0 g B, and 5.0 g C were separated by recrystallization using ethyl acetate as the recrystallization solvent. Shown below are the solubilities (in g/100 mL solvent) of A, B, and C in ethyl acetate. A B C cold hot cold hot cold Hot 1.7 2.5 2.2 3.6 1.6 5.3 What is the percent recovery of the purified crystal after one recrystallization? Answer: 51.33
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