For the spring system shown in the above figure, determine the displacement of each node. In the figure, the unit for the stiffness k is pound (lb) per inch. The left side of the system is fixed to a rigid wall, while the right side is displaced 0.5 inch to the right. Put a node between the rigid wall on the left and spring 1. Use the element method to establish the element stiffness matrix and then the global stiffness matrix. Apply the boundary conditions and the loads (by modifying the appropriate rows of the matrix and load vector). Solve the set of linear equations either by hand or using Matlab, Mathcad or Maple.
For the spring system shown in the above figure, determine the displacement of each node. In the figure, the unit for the stiffness k is pound (lb) per inch. The left side of the system is fixed to a rigid wall, while the right side is displaced 0.5 inch to the right. Put a node between the rigid wall on the left and spring 1. Use the element method to establish the element stiffness matrix and then the global stiffness matrix. Apply the boundary conditions and the loads (by modifying the appropriate rows of the matrix and load vector). Solve the set of linear equations either by hand or using Matlab, Mathcad or Maple.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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For the spring system shown in the above figure, determine the displacement of each node. In the figure, the unit for the stiffness k is pound (lb) per inch. The left side of the system is fixed to a rigid wall, while the right side is displaced 0.5 inch to the right. Put a node between the rigid wall on the left and spring 1. Use the element method to establish the element stiffness matrix and then the global stiffness matrix. Apply the boundary conditions and the
loads (by modifying the appropriate rows of the matrix and load
Transcribed Image Text:k₁=5
k₂=8
www
10 lb
k3=5
ks=10
K4=20
10 lb
k6=20
0.5 in
M→→→
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