ad is described by the function here the boldface type indicates that G is a vector. a) Draw an FBD of this system with the distributed load. b) The distributed load is measured to be -27j kN/m at the end of the beam. Find the magnitude and line of action of the equivalent resultant force due to the distributed load G(x). G(x) = -(3x²)ĵ kN/m, z € [0, L] c) Draw the FBD of this beam using the equivalent resultant force you found in part (c). d) If the force applied to the end of the rope is F = 17.5 kN, solve for the vertical reaction force at the support (Ry) and the mass of the beam per-unit-meter (m₂). Take the magnitude of the acceleration due to gravity to be g = 9.81 m/s².

Elements Of Electromagnetics
7th Edition
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ChapterMA: Math Assessment
Section: Chapter Questions
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2. Consider the same general setup as in Problem 1, but with an additional distributed load along the beam. This distributed
load is described by the function
G(x) = -(3x²)j kN/m, z = [0, L]
where the boldface type indicates that G is a vector.
a) Draw an FBD of this system with the distributed load.
b) The distributed load is measured to be -27ĵ kN/m at the end of the beam. Find the magnitude and line of action of the
equivalent resultant force due to the distributed load G(r).
c) Draw the FBD of this beam using the equivalent resultant force you found in part (c).
d) If the force applied to the end of the rope is F = 17.5 kN, solve for the vertical reaction force at the support (Ry) and the
mass of the beam per-unit-meter (m₂). Take the magnitude of the acceleration due to gravity to be g = 9.81 m/s².
Transcribed Image Text:2. Consider the same general setup as in Problem 1, but with an additional distributed load along the beam. This distributed load is described by the function G(x) = -(3x²)j kN/m, z = [0, L] where the boldface type indicates that G is a vector. a) Draw an FBD of this system with the distributed load. b) The distributed load is measured to be -27ĵ kN/m at the end of the beam. Find the magnitude and line of action of the equivalent resultant force due to the distributed load G(r). c) Draw the FBD of this beam using the equivalent resultant force you found in part (c). d) If the force applied to the end of the rope is F = 17.5 kN, solve for the vertical reaction force at the support (Ry) and the mass of the beam per-unit-meter (m₂). Take the magnitude of the acceleration due to gravity to be g = 9.81 m/s².
1. The figure below shows a one-dimensional, horizontal beam of uniform-density in static equilibrium. The beam is supported
by a frictionless support at a point 1/3 of the way down its length (L). A rope running through a frictionless pulley is attached
to the far end of the beam. The mass of the beam per-unit-meter (m) is known, and the magnitude of the acceleration due to
gravity is g.
y
| 9
13
a) What is the total force due to the weight of the beam and where does it act?
b) Draw the free body diagram (FBD) of this beam.
c) Derive expressions for the vertical reaction force at the support (R) and the force applied to the end of the rope (F).
Your expressions should be in terms of L, m,, and g; that is, you should find Ry = f(L, mr, g) and F = f(L, mz.g).
Transcribed Image Text:1. The figure below shows a one-dimensional, horizontal beam of uniform-density in static equilibrium. The beam is supported by a frictionless support at a point 1/3 of the way down its length (L). A rope running through a frictionless pulley is attached to the far end of the beam. The mass of the beam per-unit-meter (m) is known, and the magnitude of the acceleration due to gravity is g. y | 9 13 a) What is the total force due to the weight of the beam and where does it act? b) Draw the free body diagram (FBD) of this beam. c) Derive expressions for the vertical reaction force at the support (R) and the force applied to the end of the rope (F). Your expressions should be in terms of L, m,, and g; that is, you should find Ry = f(L, mr, g) and F = f(L, mz.g).
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