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- Find the vectors that satisfy the stated conditions. NOTE: Enter the exact answers using the provided round brackets.. (a) Oppositely directed to v = (1, –8) and half the length of v. w = 4 (b) Length v17 and same direction as v = (7,0, -6). 6. 0, w = -For the section to the right, find the neutral axis due to the applied moment. (a) First work the problem in x'- y coordinate system. (b) Then work the problem in x-y coordinate system and show the final location of the neutral axis is the same. 5 mm M = 400 N·m 18.57 mm 30° 5 mm 50 mm 5 mm 50 mm OMpQupq rx F, where r is a position vector from any point on the line through P and Q to R and upo is the unit vector in the direction of line segment PQ. The unit vector upo is then multiplied by this magnitude to find the vector representation of the moment. As shown in the figure, the member is anchored at A and section AB lies in the x-y plane. The dimensions are x₁ = 1.5 m, y₁ = 1.7 m, and zi = 1.6 m. The force applied at point C is F=[-150 i+ 135j + 190 k] N. (Figure 1) Figure Yı B < 1 of 1 ▼ Submi ✓ Correct Part C Calculating the moment about AB using the position vector BC Previous Answers MAB =[ Using the position vector from B to C, calculate the moment about segment AB due to force F. Express the individual components to three significant figures, if necessary, separated by commas. View Available Hint(s) 17| ΑΣΦ ↓1 vec Submit Provide Feedback Previous Answers Request Answer X Incorrect; Try Again PPearson → O с 4 ? Res i, j, k] N m Next
- Now the cable forces need to be written in component form. This is done by multiplying the magnitude of the cables by unit vectors directed along the cables: (Use form pic to finish sentence). Pt . Given the tower height of h = 36m and the anchor distance of r = 24 m, find the unit vector directed along cable AFind the following for the vectors v = 10i+11j-2k and u=8i + 15j. a. v. u, |v|, |u| b. the cosine of the angle between v and u c. the scalar component of u in the direction of v d. the vector proj, u a. v. u= (Type an exact answer, using radicals as needed.) |v|= (Type an exact answer, using radicals as needed.) |u| = [ (Type an exact answer, using radicals as needed.) b. The cosine of the angle between v and u is (Type an exact answer, using radicals as needed.) c. The scalar component of u in the direction of v is (Type an exact answer, using radicals as needed.) d. proj, u = (Type your answer in terms of i, j, and k. Type an exact answer, using radicals as needed.)FeD Fic (10+A)m 10 m 4 m Im (30+B -5 m 1.5 m Two tractors pull the tree as shown by tying the rope behind the tractor and the rope behind the tractor C at 1.5 m above the ground D at 1 m above the ground. Find an angle O made between the two ropes A = 4 %3D The angle between the two ropes (Theta) is equal to (Degree).
- You must have to draw the FBD ,and then solve in handwritten format. [Don't Copy similar solution] Determine the moment of the force about point O. Neglect the thickness of the member. Assume F= 90Nm 3m F = 500 N Find the scalar values in each coordinate axis of force vector F.What is the magnitude of the moment done by the force about point "O" in the following figure. Hint: Determine the moment of the force 'F in Cartesian vector form then deduce the magnitude. 4 m F = (60i - 30j- 20k) N 3 m 7 m 4 m 6 m 2 m P EN Select one: O a. 600 N.m
- From the following assembly, determine the following unit vectors: AB, AC, AD. (Check images for values and image)Problem 5: Inputs: F = 81 i lb The force is applied at point A. (a) Use the cross product to compute the moment about point O. Mo = TOA X F. Express your answer as a vector. (b) Using the right-hand rule, interpret your vector result from the previous step and express this as a number with direction, CW or CCW. Use the absolute value here. (c) Use the scalar approach to compute the moment about point O. If you like, you can use the table we used for the previous problems, but a table is not required for this problem. (d) Do parts (b) and (c) jibe? Yes or no. (0, 3, 0) ft y A O F X Even though this is a 2D problem, notice that you must retain the z-term in your vector formulations. That's because the result of the cross product is a moment vector that is perpendicular to the plane containing r and F. In other words, if you're using the cross product, you are inherently constructing a 3D problem, even though the inputs look like a 2D problem.Problem 6: Inputs: a = 600 mm b= 400 mm c = 200 mm F = 100 N The line of action of the force vector passes through points B and C. B N TB (a) Use the cross product to compute the moment about point A. For this part, you must use B in F your vector formulation. That is, compute MA = B x F. Express your answer as a vector and convert "mm" to "m". a b (b) Now use a different position vector, r, in the cross product. This time use rc to to compute the moment about point A. For this part, you must use rc in your vector formulation. Compute MA = rcx F. Express your answer as a vector and convert "mm" to "m". c) Do your answers agree? Yes or no. E By the way, how do you express the force as a vector when you are only given magnitude? Don't forget what we did on the last homework assignment: Position vector → Unit vector → Force vector. y