For the grids shown in Figures P5-50, determine the nodal displacements and the local element forces. Let E = 210 GPa, G = 84 GPa, -4 4 -4 I = 2×10 m², J = 1×10 m², and -2 A = 1×10² m² . Figure P5-50 C ง 3 45° 3 m 10 kN 2 m 10 kN

Discuss what we mean by multipole moments.

.A 45 kW rated solar power system has its power output and the Solar irradiance on the PV system measured during daylight hours over a day. Based on the following data, create a scatter plot of the power output of the PV system vs the solar irradiance and comment on the relationship between the two. Based on the data, can you tell which season this day was in? Solar Irradiance on the PV system (kW/m²) 0 0.079 0.333 0.571 0.751 0.86 0.914 0.93 0.904 0.803 0.606 0.345 0.054 Power output from the PV system (kW) 0 3.098 12.438 20.124 25.703 28.498 29.587 29.69 28.798 26.264 20.434 12.223 2

6. List and explain in detail why we include disturbance term or error term in the model?

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Solve (xex + y) dx − x dy = 0

calculate x-bar  for the data shown, to two decimal places, 9,7.9,10,21.8,7

Bill Kime's bowling ball factory makes bowling balls of adult size and weight only. The standard deviation in the weight of a bowling ball produced at the factory is known to be 0.39 pounds. Each day for 24 days, the average weight, in pounds, of 9 of the bowling balls produced that day has been assessed as follows Day 1 2 3 4 5 6 Average (lb) 9.9 9.9 10.1 10.1 99 99 Day 7 8 9 10 11 12 Average (lb) Day Average (b) 13 14 15 16 17 18 10.1 10.0 10.0 10.1 10.1 10.0 9.9 10.1 10.1 10.0 10.1 10.1 Day 19 20 21 22 23 24 Average (lb) 99 10.0 10.1 9.9 10.0 10.0 a) Establish a control chart for monitoring the average weights of the bowling balls in which the upper and lower control limits are each two standard deviations from the mean What are the values of the control limits? Upper Control Limit (UCL)=b (Round your response to two decimal places)

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T = -25°C A 0.5 m × 1 m double paned window is made of two silica glass panes 1 cm thick, with air in between. Under steady conditions, linear (constant gradient) Outdoors temperature profiles are found in both silica panes, as well as the air. If the room (and the inner surface of h=18Wm²K the inner glass pane) is at a temperature of 25°C, while outdoors it is -25°C with a convection coefficient of 18 W m² K-1, what is the rate of heat loss through the window? What is the rate of heat loss if the room temperature is decreased to 20°C? Finally, what is the rate of heat loss for a room temperature of 25°C, but with one of the panes (and the air) removed? 1 cm 1 cm Room Temperature, 25° C or 20º C 0.5 mm Air, k=0.024 W m¹ K¹ Silica glass, k = 0.90 W m³ K