For the following single line diagram of a three-phase system, a three-phase fault occurs at point P and just before the fault the line voltage is 18 kV at P. Find out the transient fault current in pu and original value at point P. Take, the given kVA and kV of the Gl as the new base. [hint: the transient and sub-transient reactances of the synchronous generators are assumed to be same. But for the motors, assume that the transient one is 1.7 times of the sub-transient reactance.] 20,000 KV A 6.9KV 15% G1 7000 KVA 5KV (M 14% Tz G2 11/33KV 33/6.9 AV lond 5+j8 2 20000KVA 15070 KVA 10% 12% 25,000 KVA 6.9KV 8/% [Au tue mpedances are given per- unit values) as orebtran sient ド
For the following single line diagram of a three-phase system, a three-phase fault occurs at point P and just before the fault the line voltage is 18 kV at P. Find out the transient fault current in pu and original value at point P. Take, the given kVA and kV of the Gl as the new base. [hint: the transient and sub-transient reactances of the synchronous generators are assumed to be same. But for the motors, assume that the transient one is 1.7 times of the sub-transient reactance.] 20,000 KV A 6.9KV 15% G1 7000 KVA 5KV (M 14% Tz G2 11/33KV 33/6.9 AV lond 5+j8 2 20000KVA 15070 KVA 10% 12% 25,000 KVA 6.9KV 8/% [Au tue mpedances are given per- unit values) as orebtran sient ド
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Question
For the following single line diagram of a three-phase system, a three-phase fault occurs at point P and just before the fault the line voltage is 18 kV at P. Find out the transient fault current in pu and original value at point P. Take, the given kVA and kV of the G1 as the new base.
Answer follow image.
![For the following single line diagram of a three-phase system, a three-phase fault occurs at
point P and just before the fault the line voltage is 18 kV at P. Find out the transient fault
current in pu and original value at point P. Take, the given kVA and kV of the Gl as the
new base.
[hint: the transient and sub-transient reactances of the synchronous generators are assumed
to be same. But for the motors, assume that the transient one is 1.7 times of the sub-transient
reactance.]
20,000 KV A
6.9KV
yo00 KVA
5KV
(M)14%
G1
Tz
G2
11/33KV
33/6.9 kV
lond
5+j8 2
20000KVA
15000 KVA
10%
12%.
25,000 KVA
6.9KV
[Au tue mpedances are given
per- unit values)
8/%
as orebtran sient
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F57fe8a72-6060-4015-97e8-b608f2a9a8ee%2F0badce17-d2f2-46c3-bc11-284c42e874e3%2Fk3t359b_processed.png&w=3840&q=75)
Transcribed Image Text:For the following single line diagram of a three-phase system, a three-phase fault occurs at
point P and just before the fault the line voltage is 18 kV at P. Find out the transient fault
current in pu and original value at point P. Take, the given kVA and kV of the Gl as the
new base.
[hint: the transient and sub-transient reactances of the synchronous generators are assumed
to be same. But for the motors, assume that the transient one is 1.7 times of the sub-transient
reactance.]
20,000 KV A
6.9KV
yo00 KVA
5KV
(M)14%
G1
Tz
G2
11/33KV
33/6.9 kV
lond
5+j8 2
20000KVA
15000 KVA
10%
12%.
25,000 KVA
6.9KV
[Au tue mpedances are given
per- unit values)
8/%
as orebtran sient
2
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