For the following sets of reactions describe your reactor conditions and what type of reactor should you use to maximize the desired product D. The rates are in (mol/dm s), and concentrations are in (mol/dm³). (1) A +B →D -FIA = 10° exp (-10,000 K/T) CACB (2) D → A +B -12D = 20 exp (-2,000 K/T) Cb (3) A +B →U -13A = 103 exp (-3,000 K/T) CACB Also, consider the following parallel reactions (1) A +B → D -TIA = 10 exp (-8,000 K/T) CACB (2) A →U -12A = 26 exp (-10,800 K/T) CA (3) U → A -r3U = 10,000 exp (-15,000 K/T) CU
For the following sets of reactions describe your reactor conditions and what type of reactor should you use to maximize the desired product D. The rates are in (mol/dm s), and concentrations are in (mol/dm³). (1) A +B →D -FIA = 10° exp (-10,000 K/T) CACB (2) D → A +B -12D = 20 exp (-2,000 K/T) Cb (3) A +B →U -13A = 103 exp (-3,000 K/T) CACB Also, consider the following parallel reactions (1) A +B → D -TIA = 10 exp (-8,000 K/T) CACB (2) A →U -12A = 26 exp (-10,800 K/T) CA (3) U → A -r3U = 10,000 exp (-15,000 K/T) CU
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:For the following sets of reactions describe your reactor conditions and what type of reactor should
you use to maximize the desired product D. The rates are in (mol/dm? s), and concentrations are
in (mol/dm?).
(1) A +B → D
-TIA= 10° exp (-10,000 K/T) CACB
(2) D → A +B
-гD %3D20 еxp (-2,000 К./T) Ср
(3) A +B →U
-гЗА 3 103 еxp (-3,000 К/T) САСВ
Also, consider the following parallel reactions
(1) A +B → D
-rА3 10 еxp (-8,000 К/T) САСВ
(2) A →U
-г2А 3D 26 еxp (-10,800 К/T) СА
(3) U >A
-гзu%3D 10,000 exр (-15,000 К/T) Cu
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For step 3, are you sure that there are two undesired reactions? Should the rate for U goes to A be in the numerator, since more A is probably better than more U?
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