The following gas-phase reaction occurs in an isothermal packed-bed reactor: A → P which obeys the following non-elementary rate law: -ra' = k,C,5 1.5 Derive the expression to calculate the conversion of A (XA) as a function of the catalyst weight (W). What catalyst weight is needed to obtain 90% conversion of A if CA0 L 0.5 L. = 12.3 a min 0.813- mol k1 0.0008 and k1 kg mol 0.10 -? min L
The following gas-phase reaction occurs in an isothermal packed-bed reactor: A → P which obeys the following non-elementary rate law: -ra' = k,C,5 1.5 Derive the expression to calculate the conversion of A (XA) as a function of the catalyst weight (W). What catalyst weight is needed to obtain 90% conversion of A if CA0 L 0.5 L. = 12.3 a min 0.813- mol k1 0.0008 and k1 kg mol 0.10 -? min L
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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![The following gas-phase reaction occurs in an isothermal packed-bed reactor:
A → P
which obeys the following non-elementary rate law:
-ra' = k,Ca.5
Derive the expression to calculate the conversion of A (XA) as a function of the catalyst
weight (W). What catalyst weight is needed to obtain 90% conversion of A if C40 =
0.5
L.
a =
mol
0.0008
mol.
k, = 12.3
L.
and k, = 0.10
kg
0.813-
-?
min
min](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3b4e439c-fed2-44bf-b736-6c3c22a33013%2Fdf62d649-ef6f-49a0-a0e5-38830e0d0efe%2Fq5f7qo_processed.png&w=3840&q=75)
Transcribed Image Text:The following gas-phase reaction occurs in an isothermal packed-bed reactor:
A → P
which obeys the following non-elementary rate law:
-ra' = k,Ca.5
Derive the expression to calculate the conversion of A (XA) as a function of the catalyst
weight (W). What catalyst weight is needed to obtain 90% conversion of A if C40 =
0.5
L.
a =
mol
0.0008
mol.
k, = 12.3
L.
and k, = 0.10
kg
0.813-
-?
min
min
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