For the following program, determine the total number of items displayed. #include using namespace std; int main(){ int num = 0; while(num <= 20){ num++; cout << num << } cin.ignore(); return 0; }

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Q: This is perfect,  thank you! I have one last question: Is it possible to also add a 'for' loop…

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Q: Thanks, It was really helpful, Is there way to interest the values using loop?

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Q: What happens if we permute the loops, which appears to be a little change?

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