For the circuit shown below, a system of equation can be written:   (Rs + R2 + RL1)I1 - RsI2 - R2I3 + 0I4 - RL1I5 = V0-RsI1 + (Rs + R3 + RL2)I2 + 0I3 - R3I4 + 0I5 = -V0-R2I1 + 0I2 + (R1 + R2 + R5)I3 - R5I4 - R1I5 = 00I1 - R3I2 - R5I3 + (R3 + R4 + R5 + R6)I4 - R6I5 = 0-RL1I1 + 0I2 - R1I3 - R6I4 + (R1 + R6 + RL1 + RL3)I5 = 0 Write the system of equations in matrix form: RI = V Given the values below:R1 = 1.15 ohms, R2 = 1.25 ohms, R3 = 1.17 ohms, R4 = 1.22 ohms, R5 = 1.21 ohms, R6 = 1.19 ohmsRL1 = 297 ohms, RL2 = 245 ohms, RL3 = 375 ohmsRs = 0.75 ohmsV0 = 345,000 volts Using the MATLAB editor, make a script m-file which includes a header block:Assign values to variables for resistors and voltagesAssign variables to matrix R and array VCalculate the values of currents, I’s in amps.Present the current values. Also, we are interested in the power in each load resistor. The power in watts can be found by: PL1 = (I1 - I5)2RL1PL2 = (-I2)2RL2PL3 = (I5)2RL3 Calculate and display the power in each load.

Systems Architecture
7th Edition
ISBN:9781305080195
Author:Stephen D. Burd
Publisher:Stephen D. Burd
Chapter4: Processor Technology And Architecture
Section: Chapter Questions
Problem 9VE
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For the circuit shown below, a system of equation can be written:

 

(Rs R2 + RL1)I- RsIR2I3 + 0I4 - RL1I5 = V0
-RsI1 + (Rs + R3 + RL2)I2 + 0I3 - R3I4 + 0I5 = -V0
-R2I+ 0I2 + (R1 + R2 + R5)I3 - R5I4 - R1I5 = 0
0I1 - R3I2 - R5I3 + (R3 + R4 + R5 + R6)I4 - R6I5 = 0
-RL1I+ 0I2 - R1I3 - R6I4 + (R1 + R6 + RL1 + RL3)I5 = 0

Write the system of equations in matrix form:

RI V

Given the values below:
R1 = 1.15 ohms, R2 = 1.25 ohms, R3 = 1.17 ohms, R4 = 1.22 ohms, R5 = 1.21 ohms, R6 = 1.19 ohms
RL1 = 297 ohms, RL2 = 245 ohms, RL3 = 375 ohms
Rs = 0.75 ohms
V0 = 345,000 volts

Using the MATLAB editor, make a script m-file which includes a header block:
Assign values to variables for resistors and voltages
Assign variables to matrix R and array V
Calculate the values of currents, I’s in amps.
Present the current values.

Also, we are interested in the power in each load resistor. The power in watts can be found by:

PL1 = (I1 - I5)2RL1
PL2 = (-I2)2RL2
PL3 = (I5)2RL3

Calculate and display the power in each load.

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