A + + f2 <- function(x = z) { + } z <- 100 > f2() [1] 100
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4. What does this function return? Which principle does it illustrate?
![A
+
+
f2 <- function(x = z) {
+ }
z <- 100
> f2()
[1] 100](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F580cd851-1115-453f-9bd6-403175e6d071%2F7cd4b1c2-68a8-456e-89eb-1c7942b3df19%2Frlqy1o_processed.jpeg&w=3840&q=75)
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- Consider the following function: void fun_with_recursion(int x) { printf("%i\n", x); fun_with_recursion(x + 1); } What will happen when this function is called by passing it the value 0?in C++ 3D Vector languagePROGRAMMING LANGUAGE: C++ // vectors: overloading operators example#include <iostream>using namespace std;class counter{private:int count;public:counter():count(0){}counter(int c):count(c) {} int get_count(){return count;} counter operator++ (int){return counter(count++); } counter operator-- (int){return counter(count--);}};int main(){counter c1, c2, c3;c1++;c2--;cout<<'\n'<<c1.get_count();cout<<'\n'<<c2.get_count();cout<<endl;c3 = c1++;cout<<'\n'<<c1.get_count();cout<<'\n'<<c3.get_count();getch();return 0;} Go through the above code and write the output of the given code segment. counter c1(5), c2(10), c3;c3=c1++;c2=--c3;;cout<<”\n”<<c1.get_count();cout<<”\n”<<c2.get_count();cout<<”\n”<<c3.get_count();
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