timeouttimeoutSenderConsider the figure below (simplex communication scenario).23Seq1, 10 bytes of dataSeq2, 10 bytesSeq3, 10 bytesACK1ACK2XAACK4Seq4ACK3The initial SEQ Number (Seq1) is 567.1.1232.3.What is Seq2 and Seq3What is ACK1, ACK2, Ack3What is Seq4 and ACK4Receiver3

The sequence of events in the simplex communication :1. Seq2 and Seq3:The initial sequence number…

Answered: timeout timeout Sender Consider the…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Given are the following codewords for an error control coding scheme data 000 011 100 codeword 00011000 00000111 10101000 . a.What is the minimum Hamming distance? b. What is the coding rate for this scheme? c. what raw data rate would be required if we need a throughput of 6 Mpbs? d. in a different situation, the number of data bits to transfer is 5, and the minimum hamming distance is dmin=5. find the maximum coding rate for this situation
Next time you snap a picture, you realize you are capturing millions of pixels into a buffer. The buffer data is read and converted into JPEG in real time. Each pixel in that buffer is an unsigned int (four bytes ): Alpha, Blue, Green, and Red. Let us ignore alpha for now. As you know, a unsigned byte can have a value 0 to 255. In remote sensing jargons, it is called blue channel, green channel, and red channel. Each channel provides valuable information such as, say farm lands, forest fire, drought, landscape, diseases , If a pixel has a value (say in hex) = 0x00a1b1c1 , then 0xc1 is the red pixel, 0xb1 is the green pixel, 0xa1 is the blue and 00 is the alpha. #define RED 1 #define GREEN 2 #define BLUE 3 then, develop a function void calculateSum ( unsigned int *ptr , int count , unsigned char channel , unsigned int *sum, float *average ) { *sum = 0; if (channel == RED ) calculate sum and average for red channel else if (channel == GREEN )…
Used C PLUS PLUS LANGUAGE. all instructions are given in question. Kindly follow it. When a message is transmitted in secret code over a transmission channel, it is usually sent as a sequence of bits, that is, 0s and 1s. Due to noise in the transmission channel, the transmitted message may become corrupted. That is, the message received at the destination is not the same as the message transmitted; some of the bits may have been changed. There are several techniques to check the validity of the transmitted message at the destination. One technique is to transmit the same message twice. At the destination, both copies of the message are compared bit by bit. If the corresponding bits are the same, the message received is error-free. Response Required: Write a program to check whether the message received at the destination is error-free. For simplicity, assume that the secret code representing the message is a sequence of digits (0 to 9) and the maximum length of the message is 250…
This is what my professor said: Items are 4 bytes, pages are 2k, so ~512 items fit on a page. Even if we start in the beginning of a page, the first access will be a miss followed by ~200 hits, then a TLB miss followed by ~500 hits, so the hit rate is ~100%5. Page size 512 means 9 bits of offset and 7 bits of VPN. The offset is just the decimal version of 1 0111 0111 [unsigned] which is 375The offset is 0011 100 which is 28. Is he correct?
Question: The Enigma device has to be resolved by Alan Turing and his team. You have been chosen as one of the smartest minds in the world. The device is producing codes like this; Incoming stream: HHLLHLHLL ——> the expected output: 12543761098 Incoming stream: LLHLLHLL ——> the expected output: 321654987 Incoming stream: HHHHLLLL ——> the expected output: 123498765 Incoming stream: LHLHHH ——> the expected output: 2143567 Alan says "No output digit repeats itself!". Write a full C code to decrypt this ciphered messages. You are supposed to use stack/s as a data structure for this solution. No stack answers will not be graded.
The address field of a Frame Relay frame is 1011000000010111. What is the DLCI in decimal? What is the DLCI in binary? The address field of a Frame Relay frame is 101100000101001. Is this valid? Find the DLCI value if the first 3 bytes received is 7C 74 El in hexadecimal. Find the value of the 2-byte address field in hexadecimal if the DLCI is 178. Assume no congestion. How does Frame Relay differ from X.25? What is SONET and SONET/SDH? What are the various devices that can interconnect to SONET?
In the steps of “Append the padding bits” in SHA-512 system (shown in Figure 1), the message is padded so that its length is congruent to 896 mod 1024 or (length ≅ 896 mod 1024). State the value of the following padding field is the message length is: a) 1919 b) 1920 c) 2942
Internet Checksum. Consider the six sixteen bit numbers: 10110101 01000110 01001001 01101011 10110100 01000110 01001001 01101101 10110101 01010110 01011010 01101111 Compute the Internet Checksum field value of these six words (each word has sixteen bits) Enter the 2 bytes each as an 8-bit number with only O's and 1's, and make a single blank space between the two 8-bit numbers (e.g., 01010101 00101000). [Note: you must use bitwise XOR logic function and don't use 2's or 1's complement] Not quite. This answer is incorrect.
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A messaging system reads message as 4-digit positive integer d1d2d3d4 and stores encoding of the message e1e2e3e4 for security reason. The encoding process is as follows: ei = (di+i) mod 3 For example, if message is 4590, the encoded message is 2101. Read any arbitrary message and display the encoded message in the following format: Original message = Encoded message = language : C
An analog signal having frequency as 6,70 KHz is digitized and stored in a file. If the total time of the signal is 24 min and the file size is 3,32 Mbit , which answer is correct? O a. Bit = 6 bits Data Rate = 40,2 Kbps O b. Bit = 8 bits Data Rate = 107,2 Kbps O c. Bit = 3 bits Data Rate = 221,5 Kbps O d. Bit = 7 bits Data Rate = 93,8 Kbps O e. Bit = 7 bits Data Rate = 80,4 Kbps

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timeout timeout Sender Consider the figure below (simplex communication scenario). 23 Seq1, 10 bytes of data Seq2, 10 bytes Seq3, 10 bytes ACK1 ACK2 XA ACK4 Seq4 ACK3 The initial SEQ Number (Seq1) is 567. 1. 123 2. 3. What is Seq2 and Seq3 What is ACK1, ACK2, Ack3 What is Seq4 and ACK4 Receiver 3