Comptia A+ Core 1 Exam: Guide To Computing Infrastructure (mindtap Course List)
10th Edition
ISBN: 9780357108376
Author: Jean Andrews, Joy Dark, Jill West
Publisher: Cengage Learning
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Textbook Question
Chapter 3, Problem 10TC
THINKING CRITICALLY
If 2 bits of a byte are in error when the byte is read from ECC memory, can ECC detect the error? Can it fix the error?
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If two bits of a byte are in error when the byte is read from ECC memory, can ECC detectthe error? Can it fix the error?
Given the 12-bit Hamming code below, identify the correct 8-bit memory word it represents. You must show work.
0 1 1 0 1 1 0 0 1 1 0 1
For the ROM diagram please fill the truth table
values using hexadecimal digits only. Output 3 is
the most significative bit. A3 is the most
significative address line.
mo
ml
m2
m3
m4
m5
m6
m8
m9
ml0
ml1
m12
m13
ml4
ml5
A, A, A, A,
°o
о, о, о, о,
Decoder
Chapter 3 Solutions
Comptia A+ Core 1 Exam: Guide To Computing Infrastructure (mindtap Course List)
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, computer-science and related others by exploring similar questions and additional content below.Similar questions
- Assume you have a byte-addressable machine that uses 32-bit integers and you are storing the hex value 1234 at address 0:Q. If you wanted to increase the hex value to 123456, which byte assignment would be more efficient, big or little endian? Explain your answer.arrow_forwardUsing Emu8086, write an ALP that will print the sum of two (2) variables X and Y to memory OB55H if their values are equal; otherwise, it will print their quotient to memory location DB5SH, Declare X and Y to have the size 16 bits each.arrow_forwardSuppose we want an error-correcting code that will allow all single-bit errors to be corrected for memory words of length 10. a. How many parity bits are necessary? b. Assuming we are using the Hamming algorithm presented in this chapter to design our error-correcting code and an odd parity , find the code word to present the 10-bit information word: 1 00 1 1 00 1 1 1 We now receive the following code word: C. 10 10 1 1 0 0 0 0 10 1 1 Is this a legal code word, assuming an odd parity? If not, what is the corrected code word? (Which bit is the error bit?)arrow_forward
- A set of ten packed BCD numbers is stored in the memory location starting at 3050H. i. Write a program with a subroutine to add these numbers in BCD. If a carry is generated, save it in register B, and adjust it for BCD. The final sum will be less than 9999sCD. ii. Write a second subroutine to unpack the BCD sum stored in registers A and B, and store them in the memory locations starting at 3070H. The most significant digit (BCD4) should be stored at 3070H and the least significant digit (BCD) at 3073H.arrow_forwardshow all stepsarrow_forwardCalculate the parity of a byte with the value 31 and show the pattern stored to memory. Assume the parity bit is on the right. Suppose the most significant bit was inverted in memory, and then you read it back. Did you detect the error? What happens if the two most significant bits are inverted?arrow_forward
- A 12-bit Hamming code word containing 8 bits of data and 4 parity bits is read from memory. What was the original 8-bit data word that was written into memory if the 12-bit word read out is as follows:1. 0000111010102. 1011100001103. 101111110100arrow_forwardDon't give wrong answer.arrow_forwardHow does the ALU handle signed and unsigned integer operations, and what are the implications of overflow?arrow_forward
- Given the sequence of 16-bit control words below for the datapath in Figure 8-11 and the initial ASCII character codes in 8-bit registers, simulate the datapath to determine the alphanumeric characters in the registers after the execution of the sequence. The result is a scrambled word: what is it? 011 011 001 0 0010 0 1 RO 00000000 100 100 001 0 1001 0 1 R1 00100000 101 101 001 0 1010 0 1 R2 01000100 001 001 000 0 1011 0 1 R3 01000111 001 001 000 0 0001 0 1 R4 01010100 110 110 001 0 0101 0 1 R5 01001100 111 111 001 0 0101 0 1 R6 01000001 001 111 000 0 0000 0 1 R7 01001001arrow_forwardCorrect answer will be upvoted else downvoted.thanksarrow_forwardplease don't use AI to answer this question. hand-written solution pleasearrow_forward
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