Solve In 15 minutes please . I will like your answer TME332 QZ - Microsoft Word (Product Activation Failed)FileHomeInsertPage LayoutReferencesMailingsReviewView& CutA A Aa=,三,,章 T T ,1 TA FindAaBbCcDc AaBbCcDc AaBbC AaBbCc AaBl AI Normal T No Spaci. Heading 1Times New Roma 14abs Aa Copya ReplacePasteBI U - abe x, x AAAG= 言, 三。金,。Heading 2ChangeTitleFormat PainterStyles* Select -ClipboardFontParagraphStylesEditingNavigationSearch Document国9昌This document does notcontain headings.TME332 QZ#2To create navigation tabs,create headings in yourdocument by applyingHeading Styles.For the beam shown, use singularity functions to determine the deflection and theslope at point C.wCABВ- L/2 ––L/2Page: 1 of 1 words: 19 VEnglish (U.S.)|国单 100%+)W7:14 PMrox)969TENal11/30/2020

Answered: For the beam shown, use singularity…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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TME332 QZ - Microsoft Word (Product Activation Failed)
File
Home
Insert
Page Layout
References
Mailings
Review
View
& Cut
A A Aa
=,三,,章 T T ,1 T
A Find
AaBbCcDc AaBbCcDc AaBbC AaBbCc AaBl A
I Normal T No Spaci. Heading 1
Times New Roma 14
abs A
a Copy
a Replace
Paste
BI U - abe x, x A
A
AG= 言, 三。
金,。
Heading 2
Change
Title
Format Painter
Styles
* Select -
Clipboard
Font
Paragraph
Styles
Editing
Navigation
Search Document
国9昌
This document does not
contain headings.
TME332 QZ#2
To create navigation tabs,
create headings in your
document by applying
Heading Styles.
For the beam shown, use singularity functions to determine the deflection and the
slope at point C.
w
C
A
B
В
- L/2 ––
L/2
Page: 1 of 1 words: 19 V
English (U.S.)
|国单 100%
+)
W
7:14 PM
rox)
969
T
EN
al
11/30/2020

Expert Solution

Step 1

Support reaction at A-

$F_{y} = 0 V_{A} + W L - W L = 0 V_{A} = 0$

Moment Reaction at A-

$M_{A} = W L \times \frac{L}{2} - W L (\frac{L}{2} + \frac{L}{4}) M_{A} = \frac{W L^{2}}{2} - \frac{3 W L^{2}}{4} M_{A} = - \frac{W L^{2}}{4}$

Step 2

Equations of slope and elastic curve-

$EI \frac{d^{2} v}{d x^{2}} {=M}_{x} -Moment at x EI \frac{d^{2} v}{d x^{2}} =+ \frac{W L^{2}}{4} - WX× \frac{X}{2} +2W (X - \frac{L}{2}) \frac{(X - \frac{L}{2})}{2} EI \frac{d^{2} v}{d x^{2}} = \frac{W L^{2}}{4} - \frac{W X^{2}}{2} + W {(X - \frac{L}{2})}^{2} Singularity Function {(X - \frac{L}{2})}^{n} = {(X - \frac{L}{2})}^{n} for x≥ \frac{L}{2} otherwise =0 for x< \frac{L}{2}$

Step 3

Integrating the above equation-

$E I \frac{d v}{d x} = \frac{W L^{2}}{4} X - \frac{W X^{3}}{6} + \frac{W {(X - \frac{L}{2})}^{3}}{3} + C_{1} - 1 E I (v) = \frac{W L^{2}}{4} \frac{X^{2}}{1} - \frac{W X^{4}}{24} \frac{W {(X - \frac{L}{2})}^{4}}{12} + C_{1} X + C_{2} - 2 A t = X = 0, V = 0 C_{2} = 0 A t = X, \frac{d v}{d x} = 0 C_{1} = 0$

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